Question Description
X(t) is a real valued function of a real variable with period T. Its trigonometric Fourier Series expansion contains no terms of frequency ω = 2π (2k ) / T ; k = 1, 2,.... Also, no sine terms are present. Then x(t) satisfies the equation a)x(t) = -x(t-T)b)x(t) = -x(T-t) = -x(-t)c)x(t) = x(T-t) = -x (t-T/2)d)x(t) = x(t-T) = x(t-T/2)Correct answer is option 'D'. Can you explain this answer? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared
according to
the Mathematics exam syllabus. Information about X(t) is a real valued function of a real variable with period T. Its trigonometric Fourier Series expansion contains no terms of frequency ω = 2π (2k ) / T ; k = 1, 2,.... Also, no sine terms are present. Then x(t) satisfies the equation a)x(t) = -x(t-T)b)x(t) = -x(T-t) = -x(-t)c)x(t) = x(T-t) = -x (t-T/2)d)x(t) = x(t-T) = x(t-T/2)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mathematics 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for X(t) is a real valued function of a real variable with period T. Its trigonometric Fourier Series expansion contains no terms of frequency ω = 2π (2k ) / T ; k = 1, 2,.... Also, no sine terms are present. Then x(t) satisfies the equation a)x(t) = -x(t-T)b)x(t) = -x(T-t) = -x(-t)c)x(t) = x(T-t) = -x (t-T/2)d)x(t) = x(t-T) = x(t-T/2)Correct answer is option 'D'. Can you explain this answer?.
Solutions for X(t) is a real valued function of a real variable with period T. Its trigonometric Fourier Series expansion contains no terms of frequency ω = 2π (2k ) / T ; k = 1, 2,.... Also, no sine terms are present. Then x(t) satisfies the equation a)x(t) = -x(t-T)b)x(t) = -x(T-t) = -x(-t)c)x(t) = x(T-t) = -x (t-T/2)d)x(t) = x(t-T) = x(t-T/2)Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mathematics.
Download more important topics, notes, lectures and mock test series for Mathematics Exam by signing up for free.
Here you can find the meaning of X(t) is a real valued function of a real variable with period T. Its trigonometric Fourier Series expansion contains no terms of frequency ω = 2π (2k ) / T ; k = 1, 2,.... Also, no sine terms are present. Then x(t) satisfies the equation a)x(t) = -x(t-T)b)x(t) = -x(T-t) = -x(-t)c)x(t) = x(T-t) = -x (t-T/2)d)x(t) = x(t-T) = x(t-T/2)Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
X(t) is a real valued function of a real variable with period T. Its trigonometric Fourier Series expansion contains no terms of frequency ω = 2π (2k ) / T ; k = 1, 2,.... Also, no sine terms are present. Then x(t) satisfies the equation a)x(t) = -x(t-T)b)x(t) = -x(T-t) = -x(-t)c)x(t) = x(T-t) = -x (t-T/2)d)x(t) = x(t-T) = x(t-T/2)Correct answer is option 'D'. Can you explain this answer?, a detailed solution for X(t) is a real valued function of a real variable with period T. Its trigonometric Fourier Series expansion contains no terms of frequency ω = 2π (2k ) / T ; k = 1, 2,.... Also, no sine terms are present. Then x(t) satisfies the equation a)x(t) = -x(t-T)b)x(t) = -x(T-t) = -x(-t)c)x(t) = x(T-t) = -x (t-T/2)d)x(t) = x(t-T) = x(t-T/2)Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of X(t) is a real valued function of a real variable with period T. Its trigonometric Fourier Series expansion contains no terms of frequency ω = 2π (2k ) / T ; k = 1, 2,.... Also, no sine terms are present. Then x(t) satisfies the equation a)x(t) = -x(t-T)b)x(t) = -x(T-t) = -x(-t)c)x(t) = x(T-t) = -x (t-T/2)d)x(t) = x(t-T) = x(t-T/2)Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice X(t) is a real valued function of a real variable with period T. Its trigonometric Fourier Series expansion contains no terms of frequency ω = 2π (2k ) / T ; k = 1, 2,.... Also, no sine terms are present. Then x(t) satisfies the equation a)x(t) = -x(t-T)b)x(t) = -x(T-t) = -x(-t)c)x(t) = x(T-t) = -x (t-T/2)d)x(t) = x(t-T) = x(t-T/2)Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Mathematics tests.