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The ionization enthalpy of a hydrogen atom is 1.312 × 106 J mol-1. The energy to excite the electron from n = 1 to n = 2 is – 
  • a)
     6.56 × 105 J mol-1
  • b)
    8.51 × 105 J mol-1
  • c)
    7.56 × 105 J mol-1
  • d)
    9.84 × 105 J mol-1
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The ionization enthalpy of a hydrogen atom is 1.312 × 106J mol-1...
The energy required when an electron shifts from n = 1 to n = 2
E2 = −(1.312 × 106 × (1)²)/(2²) = −3.28 × 105 J mol-1
E1 = −1.312 × 106 J mol-1
ΔE = E2 − E1
= −3.28 × 105−(−13.2 × 106)
ΔE = 9.84 × 105 J mol-1
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The ionization enthalpy of a hydrogen atom is 1.312 × 106J mol-1. The energy to excite the electron from n = 1 to n = 2 is –a)6.56 × 105J mol-1b)8.51 × 105J mol-1c)7.56 × 105J mol-1d)9.84 × 105J mol-1Correct answer is option 'D'. Can you explain this answer?
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