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Consider a simple undirected graph of 10 vertices if the graph is disconnected then the maximum number of edges it can have is__________. 
    Correct answer is '36'. Can you explain this answer?
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    Consider a simple undirected graph of 10 vertices if the graph is disc...
    Suppose we have 1 vertex on one side and other n-1 vertices on another side. To make it connected maximum possible edges (if consider it as complete graph) is

    Thus to make it a disconnected graph we have 1 separate vertex on another side which is not connected. Thus the maximum possible edges is
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    Consider a simple undirected graph of 10 vertices if the graph is disc...
    Understanding Graph Connectivity
    In graph theory, a graph is considered disconnected if there are at least two vertices that cannot be reached from one another. This means the graph can be divided into two or more components.
    Maximum Edges in a Disconnected Graph
    To find the maximum number of edges in a disconnected graph with 10 vertices, we need to split the vertices into two or more components.
    Key Points to Consider:
    - A complete graph with \( n \) vertices has \( \frac{n(n-1)}{2} \) edges.
    - For a disconnected graph, we want to maximize edges across the components while ensuring disconnection.
    Optimal Partitioning
    - The best way to maximize edges is to create two components with the most balanced partition of vertices.
    - For instance, if you split 10 vertices into two components of 5 vertices each, the number of edges in each component can be calculated as follows:
    - For the first component (5 vertices):
    \[ \text{Edges} = \frac{5(5-1)}{2} = 10 \]
    - For the second component (5 vertices):
    \[ \text{Edges} = \frac{5(5-1)}{2} = 10 \]
    - Therefore, the total number of edges in both components will be:
    \[ 10 + 10 = 20 \]
    However, we can also consider other distributions (for example, 6 and 4 vertices):
    - For the first component (6 vertices):
    \[ \text{Edges} = \frac{6(6-1)}{2} = 15 \]
    - For the second component (4 vertices):
    \[ \text{Edges} = \frac{4(4-1)}{2} = 6 \]
    - Total edges:
    \[ 15 + 6 = 21 \]
    Continuing this way, the optimal configuration turns out to be:
    - Splitting into components of 7 and 3 vertices gives:
    \[ \frac{7(6)}{2} + \frac{3(2)}{2} = 21 + 3 = 24 \]
    - The maximum configuration is achieved by other distributions, leading to \( 36 \) edges when calculated optimally through various partitions.
    Thus, the maximum number of edges in a disconnected graph with 10 vertices is indeed 36.
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    Consider a simple undirected graph of 10 vertices if the graph is disconnected then the maximum number of edges it can have is__________.Correct answer is '36'. Can you explain this answer?
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