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What is the correct order of the capacitances of these circuits, from lowest to highest? Assume all capacitors have the same capacitance.
  • a)
    B < A < C < D
  • b)
    D < C < B < A
  • c)
    C < B < A < D
  • d)
    D < C < A < B
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
What is the correct order of the capacitances of these circuits, from ...
  • For convenience, we’ll say that the capacitance of each capacitor is 1 F; the answer is independent of what value we pick.
  • We instantly can infer the capacitance of choice “C” using the series addition formula, 1/Ctotal = 1 + 1 and so Ctotal = 1/2.
  • For circuit “D,” we first use the series formula for the bottom rung, 1/Cbottom = 1/1 + 1/1 F, to find that Cbottom = 1/2 F. We then use the parallel formula to add this rung to the capacitance of the top rung for a total capacitance of Ctotal  = 1/2 + 1 = 3/2 F
  • We can determine the capacitance of circuit “A” by first combining the two capacitors in parallel Ctotal  = 1 + 1 = 2 F. We then add this in series with the capacitor on the left to find 1/Ctotal = 1/2 + 1 F, and so Ctotal = 2/3 F
  • We recognize that circuit “B” is the same as circuit “D”, except we have to add another capacitor in series with the entirety of choice D. 1/Ctotal = 2/3 + 1 and so Ctotal = 3/5 F
  • Combining our results, we find C < B < A < D
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Most Upvoted Answer
What is the correct order of the capacitances of these circuits, from ...
  • For convenience, we’ll say that the capacitance of each capacitor is 1 F; the answer is independent of what value we pick.
  • We instantly can infer the capacitance of choice “C” using the series addition formula, 1/Ctotal = 1 + 1 and so Ctotal = 1/2.
  • For circuit “D,” we first use the series formula for the bottom rung, 1/Cbottom = 1/1 + 1/1 F, to find that Cbottom = 1/2 F. We then use the parallel formula to add this rung to the capacitance of the top rung for a total capacitance of Ctotal  = 1/2 + 1 = 3/2 F
  • We can determine the capacitance of circuit “A” by first combining the two capacitors in parallel Ctotal  = 1 + 1 = 2 F. We then add this in series with the capacitor on the left to find 1/Ctotal = 1/2 + 1 F, and so Ctotal = 2/3 F
  • We recognize that circuit “B” is the same as circuit “D”, except we have to add another capacitor in series with the entirety of choice D. 1/Ctotal = 2/3 + 1 and so Ctotal = 3/5 F
  • Combining our results, we find C < B < A < D
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What is the correct order of the capacitances of these circuits, from lowest to highest? Assume all capacitors have the same capacitance.a)B < A < C < Db)D < C < B < Ac)C < B < A < Dd)D < C < A < BCorrect answer is option 'C'. Can you explain this answer? for MCAT 2025 is part of MCAT preparation. The Question and answers have been prepared according to the MCAT exam syllabus. Information about What is the correct order of the capacitances of these circuits, from lowest to highest? Assume all capacitors have the same capacitance.a)B < A < C < Db)D < C < B < Ac)C < B < A < Dd)D < C < A < BCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for MCAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the correct order of the capacitances of these circuits, from lowest to highest? Assume all capacitors have the same capacitance.a)B < A < C < Db)D < C < B < Ac)C < B < A < Dd)D < C < A < BCorrect answer is option 'C'. Can you explain this answer?.
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