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The graph of the polynomial 2x2 - 8x + 5 cuts the y-axis at _________.
- a)(6, 0)
- b)(0, 7)
- c)(0, 5)
- d)(8, 9)
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
The graph of the polynomial 2x2- 8x + 5 cuts the y-axis at _________.a...
The graph of the polynomial 2x2 - 8x + 5 cuts the y-axis.
Hence, the value of x will be 0.
y(0) = 2(0)2 - 8(0) + 5
y = 5
The graph cuts the y-axis at (0,5)
Hence, the value of x will be 0.
y(0) = 2(0)2 - 8(0) + 5
y = 5
The graph cuts the y-axis at (0,5)
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Community Answer
The graph of the polynomial 2x2- 8x + 5 cuts the y-axis at _________.a...
Introduction:
The given polynomial is 2x^2 - 8x + 5. We need to determine the point at which the graph of this polynomial intersects the y-axis.
Step-by-step solution:
To find the y-intercept, we set x = 0 and solve for y.
Substitute x = 0:
Plug in x = 0 into the given polynomial equation:
2(0)^2 - 8(0) + 5
Simplifying, we get:
0 - 0 + 5
Which equals 5.
Conclusion:
Therefore, the y-intercept of the graph of the polynomial 2x^2 - 8x + 5 is (0, 5).
Answer:
Option c) (0, 5) is the correct answer.
The given polynomial is 2x^2 - 8x + 5. We need to determine the point at which the graph of this polynomial intersects the y-axis.
Step-by-step solution:
To find the y-intercept, we set x = 0 and solve for y.
Substitute x = 0:
Plug in x = 0 into the given polynomial equation:
2(0)^2 - 8(0) + 5
Simplifying, we get:
0 - 0 + 5
Which equals 5.
Conclusion:
Therefore, the y-intercept of the graph of the polynomial 2x^2 - 8x + 5 is (0, 5).
Answer:
Option c) (0, 5) is the correct answer.
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The graph of the polynomial 2x2- 8x + 5 cuts the y-axis at _________.a)(6, 0)b)(0, 7)c)(0, 5)d)(8, 9)Correct answer is option 'C'. Can you explain this answer?
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