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2 particles are oscillating along 2 close parallel straight lines side by side, with the same frequency and amplitude. they pass each other moving in opposite directions when their displacement is half of the amplitude. the mean position of the two particles lie on a straight line perpendicular to the paths of the two particles. the phase difference is a)π/6, b)0, c)2π/3, d)π what Is the method ?
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2 particles are oscillating along 2 close parallel straight lines side...
Problem Statement:
Two particles are oscillating along two close parallel straight lines side by side, with the same frequency and amplitude. They pass each other moving in opposite directions when their displacement is half of the amplitude. The mean position of the two particles lies on a straight line perpendicular to the paths of the two particles. Find the phase difference between the two particles.
Solution:
To solve this problem, we'll break it down into smaller steps:
Step 1: Understanding the given information
- Two particles are oscillating along two close parallel straight lines side by side.
- They have the same frequency and amplitude.
- They pass each other moving in opposite directions when their displacement is half of the amplitude.
- The mean position of the two particles lies on a straight line perpendicular to the paths of the two particles.
Step 2: Analyzing the situation
- Let's assume that the two particles are denoted by particle A and particle B.
- When particle A is at a displacement of +A/2, particle B is at a displacement of -A/2.
- The mean position of the two particles lies on a straight line perpendicular to the paths of the two particles, which means it is the line of zero displacement.
Step 3: Understanding phase difference
- Phase difference is a measure of how "out of sync" two oscillating particles are.
- It is usually represented by the symbol "Φ" (phi) and is measured in radians or degrees.
- It tells us how much one particle is ahead or behind the other in its oscillation.
Step 4: Calculating the phase difference
- Since particle A and particle B pass each other when their displacement is half of the amplitude, it means they are out of phase by half a cycle.
- In other words, when particle A is at its maximum displacement, particle B is at its minimum displacement.
- This corresponds to a phase difference of π (pi) or 180 degrees.
- Therefore, the correct answer is (d) π.
Summary:
The phase difference between the two particles is π (pi) or 180 degrees. This is because they pass each other when their displacement is half of the amplitude, indicating a half-cycle phase difference.
Two particles are oscillating along two close parallel straight lines side by side, with the same frequency and amplitude. They pass each other moving in opposite directions when their displacement is half of the amplitude. The mean position of the two particles lies on a straight line perpendicular to the paths of the two particles. Find the phase difference between the two particles.
Solution:
To solve this problem, we'll break it down into smaller steps:
Step 1: Understanding the given information
- Two particles are oscillating along two close parallel straight lines side by side.
- They have the same frequency and amplitude.
- They pass each other moving in opposite directions when their displacement is half of the amplitude.
- The mean position of the two particles lies on a straight line perpendicular to the paths of the two particles.
Step 2: Analyzing the situation
- Let's assume that the two particles are denoted by particle A and particle B.
- When particle A is at a displacement of +A/2, particle B is at a displacement of -A/2.
- The mean position of the two particles lies on a straight line perpendicular to the paths of the two particles, which means it is the line of zero displacement.
Step 3: Understanding phase difference
- Phase difference is a measure of how "out of sync" two oscillating particles are.
- It is usually represented by the symbol "Φ" (phi) and is measured in radians or degrees.
- It tells us how much one particle is ahead or behind the other in its oscillation.
Step 4: Calculating the phase difference
- Since particle A and particle B pass each other when their displacement is half of the amplitude, it means they are out of phase by half a cycle.
- In other words, when particle A is at its maximum displacement, particle B is at its minimum displacement.
- This corresponds to a phase difference of π (pi) or 180 degrees.
- Therefore, the correct answer is (d) π.
Summary:
The phase difference between the two particles is π (pi) or 180 degrees. This is because they pass each other when their displacement is half of the amplitude, indicating a half-cycle phase difference.
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2 particles are oscillating along 2 close parallel straight lines side by side, with the same frequency and amplitude. they pass each other moving in opposite directions when their displacement is half of the amplitude. the mean position of the two particles lie on a straight line perpendicular to the paths of the two particles. the phase difference is a)π/6, b)0, c)2π/3, d)π what Is the method ?
Question Description
2 particles are oscillating along 2 close parallel straight lines side by side, with the same frequency and amplitude. they pass each other moving in opposite directions when their displacement is half of the amplitude. the mean position of the two particles lie on a straight line perpendicular to the paths of the two particles. the phase difference is a)π/6, b)0, c)2π/3, d)π what Is the method ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 2 particles are oscillating along 2 close parallel straight lines side by side, with the same frequency and amplitude. they pass each other moving in opposite directions when their displacement is half of the amplitude. the mean position of the two particles lie on a straight line perpendicular to the paths of the two particles. the phase difference is a)π/6, b)0, c)2π/3, d)π what Is the method ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 particles are oscillating along 2 close parallel straight lines side by side, with the same frequency and amplitude. they pass each other moving in opposite directions when their displacement is half of the amplitude. the mean position of the two particles lie on a straight line perpendicular to the paths of the two particles. the phase difference is a)π/6, b)0, c)2π/3, d)π what Is the method ?.
2 particles are oscillating along 2 close parallel straight lines side by side, with the same frequency and amplitude. they pass each other moving in opposite directions when their displacement is half of the amplitude. the mean position of the two particles lie on a straight line perpendicular to the paths of the two particles. the phase difference is a)π/6, b)0, c)2π/3, d)π what Is the method ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 2 particles are oscillating along 2 close parallel straight lines side by side, with the same frequency and amplitude. they pass each other moving in opposite directions when their displacement is half of the amplitude. the mean position of the two particles lie on a straight line perpendicular to the paths of the two particles. the phase difference is a)π/6, b)0, c)2π/3, d)π what Is the method ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 particles are oscillating along 2 close parallel straight lines side by side, with the same frequency and amplitude. they pass each other moving in opposite directions when their displacement is half of the amplitude. the mean position of the two particles lie on a straight line perpendicular to the paths of the two particles. the phase difference is a)π/6, b)0, c)2π/3, d)π what Is the method ?.
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