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Two particles are oscillating along two close parallel straight lines side by side, with the same frequency and amplitudes. They pass each other, moving in opposite directions when their displacement is half of the amplitude. The mean positions of the two particles lie on a straight line perpendicular to the paths of the two particles. The phase difference is
(a)0
  • a)
    2?/3
  • b)
    ?
  • c)
    ?/6
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Two particles are oscillating along two close parallel straight lines...
Equation of S.H.M. is given by
x = Asin(⍵t + δ)
(⍵t + 8) is called phase.
When x = A/2.then
For second particle,
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Two particles are oscillating along two close parallel straight lines side by side, with the same frequency and amplitudes. They pass each other, moving in opposite directions when their displacement is half of the amplitude. The mean positions of the two particles lie on a straight line perpendicular to the paths of the two particles. The phase difference is(a)0a)2?/3b)?c)?/6Correct answer is option 'B'. Can you explain this answer?
Question Description
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