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What real number that should be added to the polynomial f(x) = 81x- 31, so that it is exactly divisible by 9x + 1?
  • a)
    40
  • b)
    10
  • c)
    30
  • d)
    20
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
What real number that should be added to the polynomial f(x) = 81x2- 3...
81x- 31 is exactly divisible by 9x + 1
Hence, on dividing 81x- 31 by 9x + 1
We get, 9x - 1 as quotient and remainder as -30.
So if we add 30 to 81x- 31, it will be exactly divisible by 9x + 1.
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Community Answer
What real number that should be added to the polynomial f(x) = 81x2- 3...
Understanding the Problem:
To find the real number that needs to be added to the polynomial to make it exactly divisible by 9x + 1.

Given Polynomial:
f(x) = 81x^2 - 31

Divisor:
9x + 1

Approach:
We need to find the real number 'a' such that when added to the given polynomial, the resulting polynomial is divisible by 9x + 1.
- We know that for a polynomial to be divisible by 9x + 1, the remainder should be zero when the polynomial is divided by 9x + 1.
- We can use the remainder theorem to find the value of 'a'.

Using Remainder Theorem:
- If f(x) is divisible by (x - p), then f(p) = 0.
- Here, we need to find the value of 'a' such that f(x) + a is divisible by 9x + 1.
- So, we substitute x = -1/9 in the polynomial f(x) + a and equate it to zero to find 'a'.

Calculations:
f(-1/9) + a = 0
81(-1/9)^2 - 31 + a = 0
81/81 - 31 + a = 0
1 - 31 + a = 0
-30 + a = 0
a = 30

Conclusion:
Therefore, the real number that should be added to the polynomial f(x) = 81x^2 - 31 so that it is exactly divisible by 9x + 1 is 30.
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What real number that should be added to the polynomial f(x) = 81x2- 31, so that it is exactly divisible by 9x + 1?a)40b)10c)30d)20Correct answer is option 'C'. Can you explain this answer?
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