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On the coordinate plane, each point lying on a circle has its x and y coordinates greater than or equal to zero. If the centre of the circle lies at (3,4), what is the maximum possible area of the circle?
  • a)
     6π
  • b)
     8π
  • c)
     9π
  • d)
     12π
  • e)
     16π
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
On the coordinate plane, each point lying on a circle has its x and y ...
The maximum possible area of a circle occurs when the circle has the maximum possible radius. In this case, the maximum possible radius occurs when a point on the circle is located on the x-axis or the y-axis.

If a point on the circle is located on the x-axis, its coordinates would be (r, 0) where r is the radius of the circle. Similarly, if a point on the circle is located on the y-axis, its coordinates would be (0, r) where r is the radius of the circle.

Using the distance formula, we can calculate the distance between the center of the circle (3, 4) and a point on the x-axis (r, 0) or the y-axis (0, r):

Distance = √((x2 - x1)^2 + (y2 - y1)^2)

For the x-axis:
Distance = √((r - 3)^2 + (0 - 4)^2)
= √((r - 3)^2 + 16)
= √(r^2 - 6r + 9 + 16)
= √(r^2 - 6r + 25)

For the y-axis:
Distance = √((0 - 3)^2 + (r - 4)^2)
= √(9 + (r - 4)^2)
= √(r^2 - 8r + 16 + 9)
= √(r^2 - 8r + 25)

Since the radius of the circle cannot be negative, we can set the distances equal to zero and solve for r:

√(r^2 - 6r + 25) = 0
r^2 - 6r + 25 = 0
(r - 5)(r - 5) = 0
r = 5

So, the maximum possible radius of the circle is 5.

The maximum possible area of the circle is given by the formula: A = πr^2
A = π(5^2)
A = 25π

Therefore, the maximum possible area of the circle is 25π units squared.
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