Electronics and Communication Engineering (ECE) Exam > Electronics and Communication Engineering (ECE) Questions > Consider three registers R1, R2 and R3 that s...
Start Learning for Free
Consider three registers R1, R2 and R3 that store numbers in IEEE-754 single precision floating point format. Assume that R1 and R2 contain the values (in hexadecimal notation) 0x42200000 and 0xC1200000, respectively.
If R3 = R1/R2, what is the value stored in R3?
If R3 = R1/R2, what is the value stored in R3?
- a)0x40800000
- b)0xC0800000
- c)0x83400000
- d)0xC85800000
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
Consider three registers R1, R2 and R3 that store numbers in IEEE-754 ...
In IEEE- 754 single precision format, a floating-point number is represented in 32 bits.
Converting it into Hex format gives: 0x C0800000
Sign bit value 0 means positive number, and 1 means a negative number.
The floating-point number can be obtained by formula: ± 1. M × 2(E-127)
Data:
Content of R1: 0x 42200000 (0x means Hexadecimal notation)
Content of R2: 0x C1200000
Calculation:
Content of R1 in Hex (0x) is 42200000. After converting into binary, it can be represented in IEEE- 754 format as:
Content of R1 in Hex (0x) is 42200000. After converting into binary, it can be represented in IEEE- 754 format as:
Sign bit is 0 i.e. the number is positive
Biased Exponent (E’) = 100 0010 0 = 132
Normalized Mantissa (M) = 010 0000 0000 0000 0000 0000 = .25
Therefore, the number in register R1 = + 1.25 * 2(132-127) = 1.25 × 32 = 40
Content of R2 in Hex (0x) is C1200000. After converting into binary, it can be represented in IEEE- 754 format as:
Content of R2 in Hex (0x) is C1200000. After converting into binary, it can be represented in IEEE- 754 format as:
Sign bit is 1 i.e. the number is negative
Biased Exponent (E’) = 100 0001 0 = 130
Normalized Mantissa (M) = 010 0000 0000 0000 0000 0000 = .25
Therefore, the number in register R1 = - 1.25 * 2(130-127) = -1.25 * 8 = -10
R3 = R1/R2 = 40/-10 = -4
Since the number is negative, Sign bit (MSB) = 1
Converting 4 into binary of a floating point gives: (100.0)2
Representing it into normalized form gives: (1.000000….) × 22
Therefore, Mantissa is 23 bits of all 0s
Biased Exponent (E’) = E+ 127 = 2+127 = 129 = (10000001)2
It can be represented in IEEE- 754 format as:
It can be represented in IEEE- 754 format as:
Converting it into Hex format gives: 0x C0800000
Attention Electronics and Communication Engineering (ECE) Students!
To make sure you are not studying endlessly, EduRev has designed Electronics and Communication Engineering (ECE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electronics and Communication Engineering (ECE).
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Similar Electronics and Communication Engineering (ECE) Doubts
Top Courses for Electronics and Communication Engineering (ECE)View all
Consider three registers R1, R2 and R3 that store numbers in IEEE-754 single precision floating point format. Assume that R1 and R2 contain the values (in hexadecimal notation) 0x42200000 and 0xC1200000, respectively.If R3 = R1/R2,what is the value stored in R3?a)0x40800000b)0xC0800000c)0x83400000d)0xC85800000Correct answer is option 'B'. Can you explain this answer?
Question Description
Consider three registers R1, R2 and R3 that store numbers in IEEE-754 single precision floating point format. Assume that R1 and R2 contain the values (in hexadecimal notation) 0x42200000 and 0xC1200000, respectively.If R3 = R1/R2,what is the value stored in R3?a)0x40800000b)0xC0800000c)0x83400000d)0xC85800000Correct answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Consider three registers R1, R2 and R3 that store numbers in IEEE-754 single precision floating point format. Assume that R1 and R2 contain the values (in hexadecimal notation) 0x42200000 and 0xC1200000, respectively.If R3 = R1/R2,what is the value stored in R3?a)0x40800000b)0xC0800000c)0x83400000d)0xC85800000Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider three registers R1, R2 and R3 that store numbers in IEEE-754 single precision floating point format. Assume that R1 and R2 contain the values (in hexadecimal notation) 0x42200000 and 0xC1200000, respectively.If R3 = R1/R2,what is the value stored in R3?a)0x40800000b)0xC0800000c)0x83400000d)0xC85800000Correct answer is option 'B'. Can you explain this answer?.
Consider three registers R1, R2 and R3 that store numbers in IEEE-754 single precision floating point format. Assume that R1 and R2 contain the values (in hexadecimal notation) 0x42200000 and 0xC1200000, respectively.If R3 = R1/R2,what is the value stored in R3?a)0x40800000b)0xC0800000c)0x83400000d)0xC85800000Correct answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Consider three registers R1, R2 and R3 that store numbers in IEEE-754 single precision floating point format. Assume that R1 and R2 contain the values (in hexadecimal notation) 0x42200000 and 0xC1200000, respectively.If R3 = R1/R2,what is the value stored in R3?a)0x40800000b)0xC0800000c)0x83400000d)0xC85800000Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider three registers R1, R2 and R3 that store numbers in IEEE-754 single precision floating point format. Assume that R1 and R2 contain the values (in hexadecimal notation) 0x42200000 and 0xC1200000, respectively.If R3 = R1/R2,what is the value stored in R3?a)0x40800000b)0xC0800000c)0x83400000d)0xC85800000Correct answer is option 'B'. Can you explain this answer?.
Solutions for Consider three registers R1, R2 and R3 that store numbers in IEEE-754 single precision floating point format. Assume that R1 and R2 contain the values (in hexadecimal notation) 0x42200000 and 0xC1200000, respectively.If R3 = R1/R2,what is the value stored in R3?a)0x40800000b)0xC0800000c)0x83400000d)0xC85800000Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE).
Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.
Here you can find the meaning of Consider three registers R1, R2 and R3 that store numbers in IEEE-754 single precision floating point format. Assume that R1 and R2 contain the values (in hexadecimal notation) 0x42200000 and 0xC1200000, respectively.If R3 = R1/R2,what is the value stored in R3?a)0x40800000b)0xC0800000c)0x83400000d)0xC85800000Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Consider three registers R1, R2 and R3 that store numbers in IEEE-754 single precision floating point format. Assume that R1 and R2 contain the values (in hexadecimal notation) 0x42200000 and 0xC1200000, respectively.If R3 = R1/R2,what is the value stored in R3?a)0x40800000b)0xC0800000c)0x83400000d)0xC85800000Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Consider three registers R1, R2 and R3 that store numbers in IEEE-754 single precision floating point format. Assume that R1 and R2 contain the values (in hexadecimal notation) 0x42200000 and 0xC1200000, respectively.If R3 = R1/R2,what is the value stored in R3?a)0x40800000b)0xC0800000c)0x83400000d)0xC85800000Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Consider three registers R1, R2 and R3 that store numbers in IEEE-754 single precision floating point format. Assume that R1 and R2 contain the values (in hexadecimal notation) 0x42200000 and 0xC1200000, respectively.If R3 = R1/R2,what is the value stored in R3?a)0x40800000b)0xC0800000c)0x83400000d)0xC85800000Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider three registers R1, R2 and R3 that store numbers in IEEE-754 single precision floating point format. Assume that R1 and R2 contain the values (in hexadecimal notation) 0x42200000 and 0xC1200000, respectively.If R3 = R1/R2,what is the value stored in R3?a)0x40800000b)0xC0800000c)0x83400000d)0xC85800000Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.
|
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
x
![]()
For Your Perfect Score in Electronics and Communication Engineering (ECE)
The Best you need at One Place
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup