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A 10 Ω resistor carries a current that varies as a function of time as shown. How much energy has been dissipated by the resistor after 5 s?
  • a)
    40 J
  • b)
    50 J
  • c)
    80 J
  • d)
    120 J
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A 10 Ω resistor carries a current that varies as a function of t...
Power is energy dissipated per unit time; therefore, the energy dissipated is E = PΔt. In the five-second interval during which the resistor is active, it has a 2 A current for three of those seconds. The power dissipated by a resistor R carrying a current I is P = I2R. Therefore, the energy dissipated is
E = I2RΔt =(2 A)2(10 ?)(3 s)= 4 × 10 × 3 = 120 J
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