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The characteristic equation of a feedback system is s3 + Ks2 + 5s + 10 = 0. For a stable system, the value of K should not be less than
  • a)
    1
  • b)
    2
  • c)
    3
  • d)
    4.5
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The characteristic equation of a feedback system is s3+ Ks2+ 5s + 10 =...
Concept:
The characteristic equation for a given open-loop transfer function G(s) is
1 + G(s) H(s) = 0
To find the closed system stability by using RH criteria we require a  characteristic equation. Whereas in remaining all stability techniques we require open-loop transfer function.
The nth order general form of CE is
RH table shown below:
Necessary condition: All the coefficients of the characteristic equation should be positive and real.
Sufficient Conditions for stability:
1. All the coefficients in the first column should have the same sign and no coefficient should be zero.
2. If any sign changes in the first column, the system is unstable.
And the number of sign changes = Number of poles in right of s-plane.
Calculation:
Characteristic equation: s3 + Ks2 + 5s + 10 = 0
By applying Routh tabulation method,
The system to become stable, the sign changes in the first column of the Routh table must be zero.
5K – 10 > 0 and K > 0
⇒ K > 2
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Community Answer
The characteristic equation of a feedback system is s3+ Ks2+ 5s + 10 =...
The characteristic equation of a feedback system is given by the equation s^3 + Ks^2 + 5s + 10 = 0. In order for the system to be stable, the value of K should not be less than 2.

Explanation:

1. What is a Feedback System?
- A feedback system is a control system in which the output of the system is fed back and compared with the desired input in order to make necessary adjustments to the system.

2. Characteristic Equation of a Feedback System:
- The characteristic equation of a feedback system is obtained by setting the denominator of the transfer function of the system to zero.
- In this case, the characteristic equation is given by s^3 + Ks^2 + 5s + 10 = 0.

3. Stability of a Feedback System:
- A feedback system is considered stable if all the poles of the characteristic equation have negative real parts.
- The poles of the characteristic equation are the values of 's' that make the equation equal to zero.

4. Routh-Hurwitz Stability Criterion:
- The Routh-Hurwitz stability criterion is a widely used method to determine the stability of a system using the coefficients of the characteristic equation.
- According to this criterion, for a system to be stable, all the coefficients of the characteristic equation must be positive.
- In this case, the coefficients are 1, K, 5, and 10.

5. Determining the Minimum Value of K for Stability:
- To determine the minimum value of K for stability, we need to check the signs of the coefficients.
- The first coefficient is 1, which is already positive.
- The second coefficient is K, which should be positive for stability.
- The third coefficient is 5, which is positive.
- The fourth coefficient is 10, which is positive.

6. Conclusion:
- From the Routh-Hurwitz stability criterion, we can conclude that for the system to be stable, the coefficient K should be positive.
- Among the given options, the minimum positive value for K is 2.
- Therefore, the correct answer is option 'B' (K = 2)
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The characteristic equation of a feedback system is s3+ Ks2+ 5s + 10 = 0. For a stable system, the value of K should not be less thana)1b)2c)3d)4.5Correct answer is option 'B'. Can you explain this answer?
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