Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > According to Hurwitz criterion, the character...
Start Learning for Free
According to Hurwitz criterion, the characteristic equation
s4 + 8s3 + 18s2 + 16s + 5 = 0 is
- a)Stable
- b)Marginally stable
- c)Conditionally stable
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18...
Concept:
The Routh Stability Criterion is used to test the stability of an LTI system. The conditions for stability are:
- All the coefficients of the characteristic Equation must be present and must have the same sign.
- It is necessary and sufficient that each term of the first column of the Routh Array of the Characteristic Equation is positive for the system to be stable, i.e. there should not be any sign changes in the first column of each row.
- The number of sign changes represents the number of roots on the right side of the s-plane.
- If the first term in any row of Routh Array is zero while the rest of the row has at least one non-zero term. Because of this term, the terms in the next row will become infinite.
- When all elements in any row of the Routh array are zero. This condition indicates that there are symmetrical/imaginary roots in the s-plane.
Application:
A(s) = s4 + 8s3 + 18s2 + 16s + 5
Forming the Routh array, we get:
Since there are no sign changes in the first column of the Routh array, we conclude that the system is stable.
Free Test
FREE
| Start Free Test |
Community Answer
According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18...
S^4 : 1 18 5
s^3: 8 16
s^2 : (18*8-16)/8 5
s^2 : 1 5
s^1 : -24 -
s^0: 5
From the above routh array we can say that. The first column has negative number which implies that its Unstable.
s^3: 8 16
s^2 : (18*8-16)/8 5
s^2 : 1 5
s^1 : -24 -
s^0: 5
From the above routh array we can say that. The first column has negative number which implies that its Unstable.
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18s2+ 16s + 5 = 0 isa)Stableb)Marginally stablec)Conditionally stabled)None of theseCorrect answer is option 'A'. Can you explain this answer?
Question Description
According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18s2+ 16s + 5 = 0 isa)Stableb)Marginally stablec)Conditionally stabled)None of theseCorrect answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18s2+ 16s + 5 = 0 isa)Stableb)Marginally stablec)Conditionally stabled)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18s2+ 16s + 5 = 0 isa)Stableb)Marginally stablec)Conditionally stabled)None of theseCorrect answer is option 'A'. Can you explain this answer?.
According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18s2+ 16s + 5 = 0 isa)Stableb)Marginally stablec)Conditionally stabled)None of theseCorrect answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18s2+ 16s + 5 = 0 isa)Stableb)Marginally stablec)Conditionally stabled)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18s2+ 16s + 5 = 0 isa)Stableb)Marginally stablec)Conditionally stabled)None of theseCorrect answer is option 'A'. Can you explain this answer?.
Solutions for According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18s2+ 16s + 5 = 0 isa)Stableb)Marginally stablec)Conditionally stabled)None of theseCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18s2+ 16s + 5 = 0 isa)Stableb)Marginally stablec)Conditionally stabled)None of theseCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18s2+ 16s + 5 = 0 isa)Stableb)Marginally stablec)Conditionally stabled)None of theseCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18s2+ 16s + 5 = 0 isa)Stableb)Marginally stablec)Conditionally stabled)None of theseCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18s2+ 16s + 5 = 0 isa)Stableb)Marginally stablec)Conditionally stabled)None of theseCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice According to Hurwitz criterion, the characteristic equations4+ 8s3+ 18s2+ 16s + 5 = 0 isa)Stableb)Marginally stablec)Conditionally stabled)None of theseCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup