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A sinusoidal wave (longitudinal or transverse) is propagating through a medium in the direction of -ve x-axis. The parameters of the waves are A, ω and k. The particle at x = λ/4 executes the motion y(t) = A sinωt. Possible equation of the wave isa)y(x, t) = A sin[ωt - kx + (π/2)]b)y(x, t) = A sin[ωt + kx + (π/2)]c)y(x, t) = A sin[ωt - kx - (π/2)]d)y(x, t) = A sin[ωt + kx - (π/2)]Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A sinusoidal wave (longitudinal or transverse) is propagating through a medium in the direction of -ve x-axis. The parameters of the waves are A, ω and k. The particle at x = λ/4 executes the motion y(t) = A sinωt. Possible equation of the wave isa)y(x, t) = A sin[ωt - kx + (π/2)]b)y(x, t) = A sin[ωt + kx + (π/2)]c)y(x, t) = A sin[ωt - kx - (π/2)]d)y(x, t) = A sin[ωt + kx - (π/2)]Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sinusoidal wave (longitudinal or transverse) is propagating through a medium in the direction of -ve x-axis. The parameters of the waves are A, ω and k. The particle at x = λ/4 executes the motion y(t) = A sinωt. Possible equation of the wave isa)y(x, t) = A sin[ωt - kx + (π/2)]b)y(x, t) = A sin[ωt + kx + (π/2)]c)y(x, t) = A sin[ωt - kx - (π/2)]d)y(x, t) = A sin[ωt + kx - (π/2)]Correct answer is option 'D'. Can you explain this answer?.

Solutions for A sinusoidal wave (longitudinal or transverse) is propagating through a medium in the direction of -ve x-axis. The parameters of the waves are A, ω and k. The particle at x = λ/4 executes the motion y(t) = A sinωt. Possible equation of the wave isa)y(x, t) = A sin[ωt - kx + (π/2)]b)y(x, t) = A sin[ωt + kx + (π/2)]c)y(x, t) = A sin[ωt - kx - (π/2)]d)y(x, t) = A sin[ωt + kx - (π/2)]Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of A sinusoidal wave (longitudinal or transverse) is propagating through a medium in the direction of -ve x-axis. The parameters of the waves are A, ω and k. The particle at x = λ/4 executes the motion y(t) = A sinωt. Possible equation of the wave isa)y(x, t) = A sin[ωt - kx + (π/2)]b)y(x, t) = A sin[ωt + kx + (π/2)]c)y(x, t) = A sin[ωt - kx - (π/2)]d)y(x, t) = A sin[ωt + kx - (π/2)]Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A sinusoidal wave (longitudinal or transverse) is propagating through a medium in the direction of -ve x-axis. The parameters of the waves are A, ω and k. The particle at x = λ/4 executes the motion y(t) = A sinωt. Possible equation of the wave isa)y(x, t) = A sin[ωt - kx + (π/2)]b)y(x, t) = A sin[ωt + kx + (π/2)]c)y(x, t) = A sin[ωt - kx - (π/2)]d)y(x, t) = A sin[ωt + kx - (π/2)]Correct answer is option 'D'. Can you explain this answer?, a detailed solution for A sinusoidal wave (longitudinal or transverse) is propagating through a medium in the direction of -ve x-axis. The parameters of the waves are A, ω and k. The particle at x = λ/4 executes the motion y(t) = A sinωt. Possible equation of the wave isa)y(x, t) = A sin[ωt - kx + (π/2)]b)y(x, t) = A sin[ωt + kx + (π/2)]c)y(x, t) = A sin[ωt - kx - (π/2)]d)y(x, t) = A sin[ωt + kx - (π/2)]Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of A sinusoidal wave (longitudinal or transverse) is propagating through a medium in the direction of -ve x-axis. The parameters of the waves are A, ω and k. The particle at x = λ/4 executes the motion y(t) = A sinωt. Possible equation of the wave isa)y(x, t) = A sin[ωt - kx + (π/2)]b)y(x, t) = A sin[ωt + kx + (π/2)]c)y(x, t) = A sin[ωt - kx - (π/2)]d)y(x, t) = A sin[ωt + kx - (π/2)]Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A sinusoidal wave (longitudinal or transverse) is propagating through a medium in the direction of -ve x-axis. The parameters of the waves are A, ω and k. The particle at x = λ/4 executes the motion y(t) = A sinωt. Possible equation of the wave isa)y(x, t) = A sin[ωt - kx + (π/2)]b)y(x, t) = A sin[ωt + kx + (π/2)]c)y(x, t) = A sin[ωt - kx - (π/2)]d)y(x, t) = A sin[ωt + kx - (π/2)]Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.