JEE Exam > JEE Questions > Let A = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Then...
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Let A = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Then the number of subsets of A containing exactly two elements is
- a)45
- b)20
- c)35
- d)40
- e)90
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Let A = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Then the number of subsets of...
Concept:
Combination: Selecting r objects from given n objects.
- The number of selections of r objects from the given n objects is denoted by nCr
Calculation:
Number of elements in A = 10
Number of subsets of A containing exactly two elements = Number of ways we can select 2 elements from 10 elements
⇒ Number of ways we can select 2 elements from 10 elements = 10C2 = 45
∴ Number of subsets of A containing exactly two elements = 45
Most Upvoted Answer
Let A = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Then the number of subsets of...
Concept:
Combination: Selecting r objects from given n objects.
- The number of selections of r objects from the given n objects is denoted by nCr
Calculation:
Number of elements in A = 10
Number of subsets of A containing exactly two elements = Number of ways we can select 2 elements from 10 elements
⇒ Number of ways we can select 2 elements from 10 elements = 10C2 = 45
∴ Number of subsets of A containing exactly two elements = 45
Community Answer
Let A = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Then the number of subsets of...
Explanation:
Counting subsets with exactly two elements:
To find the number of subsets of A containing exactly two elements, we need to choose 2 elements out of the 10 elements in set A. This can be done using combination formula C(n, r) = n! / [r! * (n-r)!].
Calculating the number of subsets:
C(10, 2) = 10! / [2! * 8!] = 45.
Therefore, the number of subsets of A containing exactly two elements is 45.
So, the correct answer is option 'A' (45).
Counting subsets with exactly two elements:
To find the number of subsets of A containing exactly two elements, we need to choose 2 elements out of the 10 elements in set A. This can be done using combination formula C(n, r) = n! / [r! * (n-r)!].
Calculating the number of subsets:
C(10, 2) = 10! / [2! * 8!] = 45.
Therefore, the number of subsets of A containing exactly two elements is 45.
So, the correct answer is option 'A' (45).
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Let A = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Then the number of subsets of A containing exactly two elements isa)45b)20c)35d)40e)90Correct answer is option 'A'. Can you explain this answer?
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