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Two inductors L1 = 20 mH and L2 = 40 mH are connected in series so that their equivalent inductance is 50 mH. The mutual inductance between the two coils is _______.
  • a)
    15 mH
  • b)
    10 mH
  • c)
    20 mH
  • d)
    5 mH
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Two inductors L1= 20 mH and L2= 40 mH are connected in series so that ...
Concept:
The equivalent inductance of series aiding connection is
Leq = L1 + L2 + 2M
The equivalent inductance of series opposing connection is
Leq = L1 + L2 - 2M
Calculation:
Given:
L1 = 20 mH
L2 = 40 mH
Leq = 50 mH
From the given data we can conclude that series opposing connection will be considered as the mutual index cannot be negative.
Leq = L1 + L2 - 2M
50 = 40 + 20 - 2M
M = 5 mH
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Two inductors L1= 20 mH and L2= 40 mH are connected in series so that their equivalent inductance is 50 mH. The mutual inductance between the two coils is _______.a)15 mHb)10 mHc)20 mHd)5 mHCorrect answer is option 'D'. Can you explain this answer?
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