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Which of the following pair of cations can be separated by using excess NH3 solution?
  • a)
    Bi3+(aq) and Al3+(aq)
  • b)
    Al3+(aq) and Zn2+(aq)
  • c)
    Hg2+(aq) and Pb2+(aq)
  • d)
    Cu2+(aq) and Cd2+(aq)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Which of the following pair of cations can be separated by using exces...
Bi3+ + excess NH3 → Bi(OH)3 ↓ (white)
Al3+ + excess NH3 → Al(OH)3 ↓ (white)
Zn2+ + excess NH3 → Zn(NH3)3 (clear)
Hg2+ + excess NH3 → HgO.HgNH2
Pb2+ + excess NH3 → Pb(OH)2
Cu2+ + excess NH3 → Cu(NH3)42+ (clear)
Cd2+ + excess NH3 → Cd(NH3)42+ (clear)
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Most Upvoted Answer
Which of the following pair of cations can be separated by using exces...
Explanation:

To determine which pair of cations can be separated using excess NH3 solution, we need to consider the solubility rules and the formation of complex ions.

Solubility Rules:

- Group 1 cations (Li+, Na+, K+, etc.) and ammonium ion (NH4+) are soluble and will not form precipitates.
- Most nitrate (NO3-) and acetate (CH3COO-) salts are soluble and will not form precipitates.
- Most chloride (Cl-), bromide (Br-), and iodide (I-) salts are soluble, except those of silver (Ag+), lead (Pb2+), and mercury (Hg2+).
- Most sulfate (SO42-) salts are soluble, except those of calcium (Ca2+), strontium (Sr2+), barium (Ba2+), lead (Pb2+), and silver (Ag+).
- Most hydroxide (OH-) salts are insoluble, except those of group 1 cations (Li+, Na+, K+, etc.), ammonium ion (NH4+), and barium (Ba2+).
- Most carbonate (CO32-) and phosphate (PO43-) salts are insoluble, except those of group 1 cations (Li+, Na+, K+, etc.) and ammonium ion (NH4+).

Formation of Complex Ions:

Ammonia (NH3) can form complex ions with some metal cations. These complex ions are soluble and can be separated from other cations.

Analysis:

a) Bi3+ and Al3+: Both cations have a similar charge and do not form complex ions with NH3. Therefore, they cannot be separated using excess NH3 solution.
b) Al3+ and Zn2+: Al3+ can form a complex ion with NH3, [Al(NH3)6]3+. Zn2+ does not form a complex ion with NH3. Therefore, Al3+ can be separated from Zn2+ using excess NH3 solution.
c) Hg2+ and Pb2+: Both cations do not form complex ions with NH3. Therefore, they cannot be separated using excess NH3 solution.
d) Cu2+ and Cd2+: Both cations do not form complex ions with NH3. Therefore, they cannot be separated using excess NH3 solution.

Conclusion:

The pair of cations that can be separated using excess NH3 solution is Al3+ and Zn2+.
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Question Description
Which of the following pair of cations can be separated by using excess NH3 solution?a)Bi3+(aq) and Al3+(aq)b)Al3+(aq) and Zn2+(aq)c)Hg2+(aq) and Pb2+(aq)d)Cu2+(aq) and Cd2+(aq)Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following pair of cations can be separated by using excess NH3 solution?a)Bi3+(aq) and Al3+(aq)b)Al3+(aq) and Zn2+(aq)c)Hg2+(aq) and Pb2+(aq)d)Cu2+(aq) and Cd2+(aq)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following pair of cations can be separated by using excess NH3 solution?a)Bi3+(aq) and Al3+(aq)b)Al3+(aq) and Zn2+(aq)c)Hg2+(aq) and Pb2+(aq)d)Cu2+(aq) and Cd2+(aq)Correct answer is option 'B'. Can you explain this answer?.
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