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The photo diode in the figure below has an active sensing area of 10 mm2, a sensitivity of 0.5 A/W and a dark current of 1 µA. The i-to-v converter has a sensitivity of 100 mV/µA. For an input light intensity of 4 W/m2, the output VO in volt is ____.Correct answer is '2.0'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about The photo diode in the figure below has an active sensing area of 10 mm2, a sensitivity of 0.5 A/W and a dark current of 1 µA. The i-to-v converter has a sensitivity of 100 mV/µA. For an input light intensity of 4 W/m2, the output VO in volt is ____.Correct answer is '2.0'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The photo diode in the figure below has an active sensing area of 10 mm2, a sensitivity of 0.5 A/W and a dark current of 1 µA. The i-to-v converter has a sensitivity of 100 mV/µA. For an input light intensity of 4 W/m2, the output VO in volt is ____.Correct answer is '2.0'. Can you explain this answer?.

Solutions for The photo diode in the figure below has an active sensing area of 10 mm2, a sensitivity of 0.5 A/W and a dark current of 1 µA. The i-to-v converter has a sensitivity of 100 mV/µA. For an input light intensity of 4 W/m2, the output VO in volt is ____.Correct answer is '2.0'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE). Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.

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