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A) A 132 kV line with 1·956 cm dia. conductors is built so that corona takes place if the line voltage exceeds 210 kV (r.m.s.). If the value of potential gradient at which ionisation occurs can be taken as 30 kV per cm, find the spacing between the conductors.?
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A) A 132 kV line with 1·956 cm dia. conductors is built so that corona...
Given data:
- Line voltage (V) = 132 kV (or 132,000 V)
- Diameter of conductors (d) = 1.956 cm
- Corona threshold voltage (Vc) = 210 kV (or 210,000 V)
- Potential gradient for ionization (Pg) = 30 kV/cm

To find:
- Spacing between the conductors (S)

Assumptions:
- The conductors are cylindrical and have a uniform electric field distribution.
- The corona effect occurs when the electric field intensity at the surface of the conductor reaches the ionization threshold.

Solution:

Step 1: Convert the line voltage and corona threshold voltage to the same units as the potential gradient:
- Line voltage (V) = 132,000 V
- Corona threshold voltage (Vc) = 210,000 V
- Potential gradient for ionization (Pg) = 30 kV/cm = 30,000 V/m

Step 2: Calculate the electric field intensity (E) at the surface of the conductor:
- Electric field intensity (E) = V / d
- (E) = 132,000 V / (1.956 cm / 100) = 6,746,120 V/m

Step 3: Determine if the electric field intensity exceeds the ionization threshold:
- If (E) > (Pg), corona occurs.
- If (E) < (pg),="" no="" corona="" />

Step 4: Calculate the spacing between the conductors (S) when corona occurs:
- When corona occurs, the electric field intensity at the surface of the conductor is equal to the ionization threshold:
- (E) = (Pg)
- V / d = Pg
- S = d * (V / Pg)
- S = (1.956 cm / 100) * (132,000 V / 30,000 V/m) = 8.568 cm

Conclusion:
- The spacing between the conductors should be 8.568 cm in order to avoid corona when the line voltage is 132 kV and the potential gradient for ionization is 30 kV/cm.
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it depends on the length of the conductor the capacitance of the line is proportional to the length of the transmission line their effect is negligible on the performance of short having a length less than 80 km and low voltage transmission accidents of the transmission line along with the conductances forms the shunted mittens the conductance and the transmission line is because of the leakage over the surface of the conductor considered a line consisting of two conductors and be each of radius are the distance between the conductors being Des shown in the diagram below minus the potential difference between the conductors and via's work QA charge on conductor QB charge on conductor vvab pencil difference between conductor and the Epsilon minus absolute primitivity QA plus QV = 0 so that QA equals QB - equals DBA equals data equals DB equals our substituting these values and voltage equation we get the capacitance between the conductors is cab is referred to as lying to line capacitance if the two conductors are in VR oppositely charge then the potential difference between them is zero then the potential of each conductor is given by one half bath the capacitance between each conductor and point of zero potential and is capacitive CN is called the capacitance to neut or capacitance to ground capacitance cab is the combination of two equal capacity and VN series thus capacitance to neutral is twice the capacitance between the conductors IE CN equals to Cave the absolute primitivity Epsilon is given by Epsilon equals epsilono Epsilon are where epsilano is the permittivity of the free space and Epsilon or is the relative primitivity of the medium prayer capacitance reactants between one conductor and neutral capacitance of the symmetrical three phase line let a balanced system of voltage be applied to a symmetrical three-phase line shown below the phasor diagram of the three phase line with equilateral spacing is shown below take the voltage of conductor to neutral as a reference phaser the potential difference between conductor and we can be written the similarly potential difference between conductors and sea is on adding equations one and two we get also combining equation three and four from equation 6 and 7 the line to neutral capacitance the capacitance of symmetrical three phase line is same as that of the two wire line Related: Capacitance of Transmission Lines?

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A) A 132 kV line with 1·956 cm dia. conductors is built so that corona takes place if the line voltage exceeds 210 kV (r.m.s.). If the value of potential gradient at which ionisation occurs can be taken as 30 kV per cm, find the spacing between the conductors.?
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A) A 132 kV line with 1·956 cm dia. conductors is built so that corona takes place if the line voltage exceeds 210 kV (r.m.s.). If the value of potential gradient at which ionisation occurs can be taken as 30 kV per cm, find the spacing between the conductors.? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A) A 132 kV line with 1·956 cm dia. conductors is built so that corona takes place if the line voltage exceeds 210 kV (r.m.s.). If the value of potential gradient at which ionisation occurs can be taken as 30 kV per cm, find the spacing between the conductors.? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A) A 132 kV line with 1·956 cm dia. conductors is built so that corona takes place if the line voltage exceeds 210 kV (r.m.s.). If the value of potential gradient at which ionisation occurs can be taken as 30 kV per cm, find the spacing between the conductors.?.
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