There is a ball that will burst if the pressure exceeds 0.12 bars. The...
According to Boyle’s law at a constant temperature, the pressure is inversely proportional to the temperature so here P1V1 is equaled to P1V2 by equating P1V1 is equaled to 1 x 2.5 = 2.5, so the maximum volume of the ball that can be expanded is 2.5/0.12 =0.3 liters.
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There is a ball that will burst if the pressure exceeds 0.12 bars. The...
Given:
Pressure of gas = 1 bar
Volume of gas = 2.5 liters
Maximum pressure before ball bursts = 0.12 bars
To find:
Maximum volume that the ball can be expanded
Solution:
To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional, given the temperature remains constant.
Boyle's Law:
P1V1 = P2V2
Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
Step 1:
We are given the initial pressure (P1) and volume (V1) as 1 bar and 2.5 liters, respectively.
So, P1 = 1 bar and V1 = 2.5 liters.
Step 2:
We are also given the maximum pressure (P2) before the ball bursts as 0.12 bars.
So, P2 = 0.12 bars.
Step 3:
Let's calculate the final volume (V2) using Boyle's Law.
P1V1 = P2V2
1 bar * 2.5 liters = 0.12 bars * V2
2.5 = 0.12 * V2
V2 = 2.5 / 0.12
V2 ≈ 20.83 liters
Step 4:
Since the question asks for the maximum volume that the ball can be expanded, we need to subtract the initial volume from the final volume.
Maximum volume = V2 - V1
Maximum volume = 20.83 liters - 2.5 liters
Maximum volume ≈ 18.33 liters
Therefore, the maximum volume that the ball can be expanded is approximately 18.33 liters.
Conclusion:
The correct answer is option 'C' - 0.3 liters.