To find the resolution of a 10-bit AD converter, we need to calculate the smallest change in the input voltage that can be detected by the converter.

Given information:
Input range = 10 V
Number of bits = 10

To determine the resolution, we need to find the difference between the maximum and minimum possible values of the digital output of the converter.

The maximum value of the digital output can be obtained when the input voltage is at its maximum value. In this case, the maximum value of the digital output will be the largest possible binary number that can be represented with 10 bits, which is (2^10) - 1 = 1023.

The minimum value of the digital output can be obtained when the input voltage is at its minimum value. In this case, the minimum value of the digital output will be 0.

Therefore, the resolution can be calculated as the difference between the maximum and minimum possible values of the digital output divided by the total number of possible digital output levels.

Resolution = (Maximum digital output - Minimum digital output) / Number of possible digital output levels
= (1023 - 0) / (2^10)
= 1023 / 1024
= 0.999

Since we are dealing with digital outputs, the resolution cannot be fractional. Therefore, we round the resolution value to the nearest whole number.

Hence, the resolution of a 10-bit AD converter for an input range of 10 V is 1 V.

However, none of the given options match the correct answer. The closest option is option 'B' which states 9.77 mV. This is incorrect.