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What is the standard form for the resolution of a vector having magnitude ‘a’ and is inclined at an angle θ to the X-axis?
  • a)
    a(cos θ î + sin θ ĵ)
  • b)
    a(sin θ î + cos θ ĵ)
  • c)
    a(sin θ î + sin θ ĵ)
  • d)
    a(cos θ î + cos θ ĵ)
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
What is the standard form for the resolution of a vector having magnit...
The correct answer is a(cos θ î + sin θ ĵ). This is obtained by constructing a right-angled triangle with the distance of the point from the origin with either of the axes and then finding out the corresponding values for X and Y components.
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Most Upvoted Answer
What is the standard form for the resolution of a vector having magnit...
The standard form for the resolution of a vector with a magnitude is:

V = Vcosθ + Vsinθ

where V is the magnitude of the vector, θ is the angle the vector makes with the x-axis, Vcosθ is the horizontal component of the vector, and Vsinθ is the vertical component of the vector.
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What is the standard form for the resolution of a vector having magnitude ‘a’ and is inclined at an angle θ to the X-axis?a)a(cos θ î + sin θ )b)a(sin θ î + cos θ )c)a(sin θ î + sin θ )d)a(cos θ î + cos θ )Correct answer is option 'A'. Can you explain this answer?
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