SD of x is 3 then whats the varience of (5-2x)?
Calculating the Variance of (5-2x) Given SD of x is 3
Step 1: Find the Mean of (5-2x)
The mean of (5-2x) can be calculated as follows:
E(5-2x) = E(5) - 2E(x)
= 5 - 2μ (where μ is the mean of x)
Step 2: Find the Variance of (5-2x)
To find the variance of (5-2x), we need to use the formula:
Var(5-2x) = E[(5-2x)^2] - [E(5-2x)]^2
Substituting the values from step 1, we get:
Var(5-2x) = E[(5-2x)^2] - [5-2μ]^2
Step 3: Simplify the Formula
We can simplify the formula by expanding the square:
Var(5-2x) = E[25 - 20x + 4x^2] - [25 - 10μ + 4μ^2]
= E(25) - 20E(x) + 4E(x^2) - 25 + 10μ - 4μ^2
= 4E(x^2) - 20μ + 10μ - 4μ^2
= 4E(x^2) - 4μ^2 - 20μ
Step 4: Use the SD of x to Find E(x^2)
We know that SD of x is 3. So, we can use the formula:
SD(x)^2 = E(x^2) - [E(x)]^2
Substituting the values, we get:
9 = E(x^2) - μ^2
E(x^2) = 9 + μ^2
Step 5: Plug in the Values to Find Var(5-2x)
Plugging this value in the formula from step 3, we get:
Var(5-2x) = 4(9 + μ^2) - 4μ^2 - 20μ
= 36 + 4μ^2 - 4μ^2 - 20μ
= 36 - 20μ
Therefore, the variance of (5-2x) is 36 - 20μ.
SD of x is 3 then whats the varience of (5-2x)?
X=3 , SD of y = |b| SD of x = 2 × 3 = 6 variance = SD square = 6 ^2 = 36.