A bus moves the first few meters of its journey with an acceleration o...
Apply the first equation of motion in both the parts. For first part, v1 = u + a1t1 = 0 + 5×10 = 50 m/s. For second part, v2 = u2 (= v1) + a2t2 = 50 + 15×20 = 350 m/s.
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A bus moves the first few meters of its journey with an acceleration o...
The problem provides information about the acceleration and time intervals for two different parts of the bus's journey. We need to find the final velocity of the bus starting from rest.
Let's break down the problem into two parts and calculate the velocities separately.
First Part of the Journey:
- Acceleration (a1) = 5 m/s^2
- Time (t1) = 10 s
Using the equation of motion: v = u + at, where v is the final velocity, u is the initial velocity (which is 0 in this case), a is the acceleration, and t is the time, we can calculate the velocity at the end of the first part of the journey.
v1 = u + a1t1
= 0 + (5 m/s^2)(10 s)
= 50 m/s
Second Part of the Journey:
- Acceleration (a2) = 15 m/s^2
- Time (t2) = 20 s
Using the same equation of motion, we can calculate the velocity at the end of the second part of the journey.
v2 = u + a2t2
= 0 + (15 m/s^2)(20 s)
= 300 m/s
Total Velocity:
To find the total velocity, we can add the velocities from the two parts of the journey since there is no change in velocity between the two parts.
Total velocity (v) = v1 + v2
= 50 m/s + 300 m/s
= 350 m/s
Therefore, the final velocity of the bus is 350 m/s (option B).