Physics Exam > Physics Questions > A system absorb 1.2×10^3 k cal of heat and do...
Start Learning for Free
A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calculate the change in the internal energy of the system. Given mechanical equivalent of heat J = 4.186 J/cal?
Most Upvoted Answer
A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calc...
Given:
- Heat absorbed by the system = 1.2×10^3 k cal
- Work done by the system = 1.7×10^7 J
- Mechanical equivalent of heat = 4.186 J/cal
To Find:
Change in the internal energy of the system
Explanation:
The change in the internal energy of a system can be determined using the first law of thermodynamics, which states that the change in the internal energy of a system is equal to the heat added to the system minus the work done by the system.
Formula:
Change in internal energy (ΔU) = Heat absorbed (Q) - Work done (W)
Calculations:
1. Convert the heat absorbed from kcal to J.
Heat absorbed (Q) = 1.2×10^3 kcal × 4.186 J/cal
= 5.0232×10^3 kJ
2. Plug the values into the formula to calculate the change in internal energy.
ΔU = Q - W
= 5.0232×10^3 kJ - 1.7×10^7 J
3. Convert the units to a common unit (J) before performing the subtraction.
ΔU = 5.0232×10^3 kJ - 1.7×10^7 J
= 5.0232×10^3 kJ - 1.7×10^7 J
= -1.1977×10^7 J
Answer:
The change in the internal energy of the system is -1.1977×10^7 J.
- Heat absorbed by the system = 1.2×10^3 k cal
- Work done by the system = 1.7×10^7 J
- Mechanical equivalent of heat = 4.186 J/cal
To Find:
Change in the internal energy of the system
Explanation:
The change in the internal energy of a system can be determined using the first law of thermodynamics, which states that the change in the internal energy of a system is equal to the heat added to the system minus the work done by the system.
Formula:
Change in internal energy (ΔU) = Heat absorbed (Q) - Work done (W)
Calculations:
1. Convert the heat absorbed from kcal to J.
Heat absorbed (Q) = 1.2×10^3 kcal × 4.186 J/cal
= 5.0232×10^3 kJ
2. Plug the values into the formula to calculate the change in internal energy.
ΔU = Q - W
= 5.0232×10^3 kJ - 1.7×10^7 J
3. Convert the units to a common unit (J) before performing the subtraction.
ΔU = 5.0232×10^3 kJ - 1.7×10^7 J
= 5.0232×10^3 kJ - 1.7×10^7 J
= -1.1977×10^7 J
Answer:
The change in the internal energy of the system is -1.1977×10^7 J.
|
Explore Courses for Physics exam
|
|
Similar Physics Doubts
A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calculate the change in the internal energy of the system. Given mechanical equivalent of heat J = 4.186 J/cal?
Question Description
A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calculate the change in the internal energy of the system. Given mechanical equivalent of heat J = 4.186 J/cal? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calculate the change in the internal energy of the system. Given mechanical equivalent of heat J = 4.186 J/cal? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calculate the change in the internal energy of the system. Given mechanical equivalent of heat J = 4.186 J/cal?.
A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calculate the change in the internal energy of the system. Given mechanical equivalent of heat J = 4.186 J/cal? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calculate the change in the internal energy of the system. Given mechanical equivalent of heat J = 4.186 J/cal? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calculate the change in the internal energy of the system. Given mechanical equivalent of heat J = 4.186 J/cal?.
Solutions for A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calculate the change in the internal energy of the system. Given mechanical equivalent of heat J = 4.186 J/cal? in English & in Hindi are available as part of our courses for Physics.
Download more important topics, notes, lectures and mock test series for Physics Exam by signing up for free.
Here you can find the meaning of A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calculate the change in the internal energy of the system. Given mechanical equivalent of heat J = 4.186 J/cal? defined & explained in the simplest way possible. Besides giving the explanation of
A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calculate the change in the internal energy of the system. Given mechanical equivalent of heat J = 4.186 J/cal?, a detailed solution for A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calculate the change in the internal energy of the system. Given mechanical equivalent of heat J = 4.186 J/cal? has been provided alongside types of A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calculate the change in the internal energy of the system. Given mechanical equivalent of heat J = 4.186 J/cal? theory, EduRev gives you an
ample number of questions to practice A system absorb 1.2×10^3 k cal of heat and does work 1.7×10^7 J . Calculate the change in the internal energy of the system. Given mechanical equivalent of heat J = 4.186 J/cal? tests, examples and also practice Physics tests.
|
|
Explore Courses for Physics exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup