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A compound contains 4.07%hydrogen , 24.27% carbon and rest chlorine, then find its empirical formula???? ? molecular mass is 98.96
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A compound contains 4.07%hydrogen , 24.27% carbon and rest chlorine, t...
Let total mass of the molecule = 100g....Mass of C in the molecule = 24.27g....Mass of H in the molecule = 4.07g....Mass of Cl in the molecule =71.65 g..... Number of moles of C in molecule = 24.27/ molar mass of carbon = 24.27 /12 = 2.02.......Number of moles of H in molecule = 4.07/ molar mass of hydrogen = 4.07 /1 = 4.07......Number of moles of Cl in molecule = 71.65/ molar mass of nitrogen = 71.65 /35.45 =2.02..... Ratio of the number of moles of C, H & Cli.e.C:H:Cl = 2.02 : 4.07 : 2.02 = 1:2:1So the empirical formula will be..CH2ClEmpirical formula mass = 12.01+2+35.45 = 49.5 g Now n = Molecular mass/ empirical formula mass = 98.96/49.5 = 2 Molecular formula = n x empirical formula = 2(CH2Cl) = C2H4Cl2.
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A compound contains 4.07%hydrogen , 24.27% carbon and rest chlorine, t...
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A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the original compound A is treated with LiAIH4 a new compound D(C7H14) would be produced. How many different structure(s) can be drawn for this D ?

A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is brominated in gas phase in the presence of a Lewis acid catalyst, a tribromide would result from addition of Br2 to . How many different structures of stereoisomers can be drawn for this tribromide?

A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.If the starting compound A is treated with ethanolic solution of KOH in boiling condition, a further new compound E (C7H12) is produced as major product by E2 elimination reaction. Which of the following statement will be consistent with E?

A chemist isolated a compound A with molecular formula C7H13Br. A undergoes very fast SN1 reaction. Spectroscopic evidence indicated that compound A has the following structural characteristics : It contains five sp3-hybridised carbon atoms. Among those five sp3 carbon atoms, three are methyl groups, one CH2 group and one CH group.It also contains two sp2-hybridised carbon atoms. Also there is only one hydrogen atom attached to sp2 carbons.The compound contains a total of six aliylic hydrogen atoms.The carbon atom that holds the Br has one H attached to it.Working SpaceWhen compound A reacts with boiling water, it undergoes a SN1 reaction and produces two principal products B and C. Both B and C are alcohols with their molecular formula C7H14O. Among the two alcohols, B has the OH group attached to a sp3 carbon atom that has no H -atoms bonded to it.Q.What can be said about the isomerism shown by the two alcohols B and C ?

A compound contains 4.07%hydrogen , 24.27% carbon and rest chlorine, then find its empirical formula???? ? molecular mass is 98.96
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