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The sum of 40 terms of an A.P. whose first term is 2 and common difference 4, will be
- a)3200
- b)1600
- c)200
- d)2800
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The sum of 40 terms of an A.P. whose first term is 2 and common differ...
Concept:
Sum of the n terms in an A.P. = n/2(2a+(n−1)d)
Where n = Number of terms,
a = First Term,
d = Common Difference.
Sum of the n terms in an A.P. = n/2(2a+(n−1)d)
Where n = Number of terms,
a = First Term,
d = Common Difference.
Explanation:
We have to find the sum of 40 terms of an A.P. whose first term is 2 and common difference 4
i.e.
n = 40, a = 2 and d = 4
Thus,
Sum = 40/2(2(2)+(40−1)(4))
⇒ Sum = 20 × (4 + (39 × 4))
⇒ Sum = 20 × (160)
⇒ Sum = 3200
We have to find the sum of 40 terms of an A.P. whose first term is 2 and common difference 4
i.e.
n = 40, a = 2 and d = 4
Thus,
Sum = 40/2(2(2)+(40−1)(4))
⇒ Sum = 20 × (4 + (39 × 4))
⇒ Sum = 20 × (160)
⇒ Sum = 3200
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The sum of 40 terms of an A.P. whose first term is 2 and common difference 4, will bea)3200b)1600c)200d)2800Correct answer is option 'A'. Can you explain this answer?
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