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A signal having a bandwidth of 5 MHz is transmitted using the Pulse code modulation (PCM) scheme as follows. The signal is sampled at a rate of 50% above the Nyquist rate and quantized into 256 levels. The binary pulse rate of the PCM signal in Mbits per second is ___.
  • a)
    120
  • b)
    134
  • c)
    340
  • d)
    145
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A signal having a bandwidth of 5 MHz is transmitted using the Pulse co...
Given Information:
- Bandwidth of the signal = 5 MHz
- Sampling rate = 50% above the Nyquist rate
- Quantization levels = 256

Calculation:

Step 1: Nyquist Rate Calculation
Nyquist rate is twice the bandwidth of the signal. Hence,
Nyquist rate = 2 x 5 MHz = 10 MHz

Step 2: Sampling Rate Calculation
Sampling rate = 1.5 x Nyquist rate = 1.5 x 10 MHz = 15 MHz

Step 3: Number of bits per sample Calculation
Given that the signal is quantized into 256 levels, we need log2(256) = 8 bits per sample.

Step 4: Binary Pulse Rate Calculation
Binary pulse rate = Sampling rate x Number of bits per sample
Binary pulse rate = 15 MHz x 8 = 120 Mbits per second
Therefore, the binary pulse rate of the PCM signal is 120 Mbits per second. So, the correct answer is option 'A'.
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A signal having a bandwidth of 5 MHz is transmitted using the Pulse co...


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A signal having a bandwidth of 5 MHz is transmitted using the Pulse code modulation (PCM) scheme as follows. The signal is sampled at a rate of 50% above the Nyquist rate and quantized into 256 levels. The binary pulse rate of the PCM signal in Mbits per second is ___.a)120b)134c)340d)145Correct answer is option 'A'. Can you explain this answer?
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