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The number of integers n satisfying -n + 2 ≥ 0 and 2n ≥ 4 is
  • a)
    1
  • b)
    0
  • c)
    2
  • d)
    3
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The number of integers n satisfying -n + 2 ≥ 0 and 2n ≥ 4 isa)1b...
First inequality:
-n + 2 ≥ 0
-n ≥ -2
n ≤ 2
Second inequality:
2n ≥ 4
n ≥ 2
Only n = 2 satisfies both inequalities. So, there is only 1 integer that satisfies both the inequalities.
The correct option is A.
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Most Upvoted Answer
The number of integers n satisfying -n + 2 ≥ 0 and 2n ≥ 4 isa)1b...
To find the number of integers n satisfying the given inequality, we need to consider two cases:

Case 1: -n + 2 > 0
In this case, we have -n > -2, which means n < 2.="" since="" n="" has="" to="" be="" an="" integer,="" the="" possible="" values="" for="" n="" in="" this="" case="" are="" n="1" and="" n="0." />

Case 2: -n + 2 < />
In this case, we have -n < -2,="" which="" means="" n="" /> 2. Again, since n has to be an integer, there are no integers satisfying this condition.

Therefore, the only integers that satisfy the given inequality are n = 1 and n = 0.
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The number of integers n satisfying -n + 2 ≥ 0 and 2n ≥ 4 isa)1b)0c)2d)3Correct answer is option 'A'. Can you explain this answer?
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