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If n c r-1=56 , n c r =28 and n cr+1 =8 then r is equal to?? plzz solve it?
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If n c r-1=56 , n c r =28 and n cr+1 =8 then r is equal to?? plzz solv...
Divide nCr-1 and nCr ( i.e. nCr-1/nCr =56/28).. So after solving we get the foll. Eqn. 3r=2n+2 .... Now similarly divide nCr/nCr+1 = 28 /8 ... So we get another eqn. That is 9r= 7n-2.. Now solving these two equations we will get r=6..
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Most Upvoted Answer
If n c r-1=56 , n c r =28 and n cr+1 =8 then r is equal to?? plzz solv...
Solve 2 equations simultaneously.eqn 1: [n!/(r-1)!(n-(r-1))!]÷[n!/r!(n-r)! = 56/28eqn 2: [n!/(r+1)!(n-(r+1))!]÷[n!/r!(n-r)! = 8/28you'll get 2 eqns, solve them and you'll get the value of r.
Community Answer
If n c r-1=56 , n c r =28 and n cr+1 =8 then r is equal to?? plzz solv...
Given:
nCr-1 = 56
nCr = 28
nCr+1 = 8

To find:
The value of r

Solution:
Let's start by understanding the concept of combinations and the formula for nCr.

In mathematics, combinations are ways to select items from a larger set without considering the order. The formula for combinations is given by:

nCr = n! / (r!(n-r)!)

Where n is the total number of items, r is the number of items to be selected, and ! denotes factorial, which means multiplying a number with all the positive integers less than it.

Now, let's solve the given problem step by step.

Step 1:
Given that nCr-1 = 56 and nCr = 28, we can write the following equations:

nCr-1 = n! / ((r-1)!(n-r+1)!) = 56
nCr = n! / (r!(n-r)!) = 28

Step 2:
To simplify the equations, we can divide the two equations:

(n! / ((r-1)!(n-r+1)!)) / (n! / (r!(n-r)!)) = 56 / 28

Simplifying further, we get:

(r!(n-r)!)/( (r-1)!(n-r+1)! ) = 2

Step 3:
Now, let's simplify the factorial terms:

(r!(n-r)!)/( (r-1)!(n-r+1)! ) = 2
(r!(n-r)!)/( (r-1)!(n-r+1)(n-r)! ) = 2
(r!)/( (r-1)!(n-r+1) ) = 2

Step 4:
Expanding the factorial terms:

(r(r-1)!)/( (r-1)!(n-r+1) ) = 2

Simplifying further, we get:

r = 2(n-r+1)

Step 5:
Given that nCr+1 = 8, we can write the equation:

nCr+1 = n! / ((r+1)!(n-r-1)!) = 8

Expanding the factorial terms:

n! / ((r+1)!(n-r-1)!) = 8

Step 6:
Substituting the value of nCr from the previous equation:

28 / ((r+1)!((n-r)!)(n-r-1)!) = 8

Simplifying further, we get:

(r+1)!((n-r)!)(n-r-1)! = 28/8 = 7/2

Step 7:
Since r is a positive integer, the only possible value for (r+1)! is 3.

Therefore, (r+1)! = 3

Step 8:
Solving for r:

r+1 = 3
r = 3 - 1
r = 2

Answer:
The value of r is 2.
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If n c r-1=56 , n c r =28 and n cr+1 =8 then r is equal to?? plzz solve it?
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If n c r-1=56 , n c r =28 and n cr+1 =8 then r is equal to?? plzz solve it? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If n c r-1=56 , n c r =28 and n cr+1 =8 then r is equal to?? plzz solve it? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If n c r-1=56 , n c r =28 and n cr+1 =8 then r is equal to?? plzz solve it?.
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