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Evaluate |x3+y3−3xyz| when x=−2,y=−1 and z=3.
  • a)
    27
  • b)
    17
  • c)
    36
  • d)
    77
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Evaluate|x3+y3−3xyz|whenx=−2,y=−1andz=3.a)27b)17c)36...
x3+y3−3xyz = (−2)3+(−1)3−3×(−2)×(−1)×3 = −8−1−18 = −27
|x3+y3−3xyz| = 27
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Evaluate|x3+y3−3xyz|whenx=−2,y=−1andz=3.a)27b)17c)36d)77Correct answer is option 'A'. Can you explain this answer?
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