If alpha and beta are the zeroes of p(x) = 2x^2 - 5x +3. then find a q...
Quadratic Polynomial with Zeroes 1/alpha and 1/beta:
To find a quadratic polynomial with zeroes 1/alpha and 1/beta, we need to understand the relationship between the zeroes of a quadratic polynomial and its coefficients. A quadratic polynomial is given in the form:
p(x) = ax^2 + bx + c
where 'a', 'b', and 'c' are the coefficients of the polynomial.
Relationship between Zeroes and Coefficients:
For a quadratic polynomial, the sum of the zeroes is equal to the negation of the coefficient of the linear term (b/a), and the product of the zeroes is equal to the constant term (c/a).
Let's consider the given quadratic polynomial:
p(x) = 2x^2 - 5x + 3
Here, the sum of the zeroes is equal to -(-5/2) = 5/2, and the product of the zeroes is equal to 3/2.
Finding the Zeroes:
We are given that alpha and beta are the zeroes of the polynomial p(x) = 2x^2 - 5x + 3.
Using the quadratic formula, we can find the zeroes:
x = (-b ± √(b^2 - 4ac))/(2a)
Substituting the values of 'a', 'b', and 'c' from the given polynomial, we have:
x = (-(-5) ± √((-5)^2 - 4(2)(3)))/(2(2))
x = (5 ± √(25 - 24))/(4)
x = (5 ± √(1))/(4)
x = (5 ± 1)/(4)
One zero is obtained when we take the positive square root:
x = (5 + 1)/(4) = 6/4 = 3/2
Another zero is obtained when we take the negative square root:
x = (5 - 1)/(4) = 4/4 = 1
Therefore, the zeroes of the polynomial p(x) = 2x^2 - 5x + 3 are 3/2 and 1.
Finding the Quadratic Polynomial with Zeroes 1/alpha and 1/beta:
Now, we want to find a quadratic polynomial with zeroes 1/alpha and 1/beta.
Let's consider a new quadratic polynomial:
q(x) = k(x - 1/alpha)(x - 1/beta)
Here, 'k' is a constant that can be any non-zero value.
The zeroes of the polynomial q(x) are