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The rotational spectrum of 12C16O shows the gap between the spectral lines from J"=3→4 to J" =9→10 is 24 cm-1. The rotational constant of 13C16O in cm-1 is closest to
- a)2.98
- b)0.88
- c)1.90
- d)2.08
Correct answer is option 'C'. Can you explain this answer?
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The rotational spectrum of 12C16O shows the gap between the spectral l...
- Now, the energy separation of 12C16O rotational energy levels between J"=3 and J" = 9 is 24 cm-1.
- From the rotation energy level J"=3 to J" = 9, there are 7 energy levels and 6 spectral lines. These are for 3→4, 4→5, 5→6, 6→7, 7→8, 8→9 transitions.
- The energy separation between the two successive spectral lines is 2B. Thus, the energy separation between rotation energy level J"=3 to J" = 9 is 12B (6 spectral lines = 2B×6 = 12B).
- Hence, 12B = 24cm−1
- Thus for 12C16O,
B12C16O=2cm−1 - As the reduced mass changes (μ) the value of rotational constant (B) also changes as
≈1.9 - So, the value of rotational constant B for 13C16O is closest to 1.9 cm-1.
Thus, the rotational constant of 13C16O in cm-1 is closest to 1.9 cm-1.
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The rotational spectrum of 12C16O shows the gap between the spectral l...
The gap between the spectral lines from J in the rotational spectrum of 12C16O is determined by the selection rule for rotational transitions.
The selection rule states that the change in the rotational quantum number (ΔJ) between two energy levels must be ±1. This means that transitions between adjacent energy levels are allowed, while transitions between non-adjacent energy levels are not.
In the rotational spectrum of 12C16O, the energy levels are determined by the rotational quantum number J. The value of J can be any non-negative integer, with J = 0 representing the lowest energy level.
The gap between the spectral lines from J is therefore given by the difference in energy levels between two adjacent values of J. This difference can be determined using the formula:
ΔE = (h^2 / 8π^2I) * (J+1)
Where ΔE is the energy difference between two adjacent levels, h is Planck's constant, and I is the moment of inertia for the molecule.
By calculating ΔE for two adjacent values of J, you can determine the gap between the spectral lines in the rotational spectrum of 12C16O.
The selection rule states that the change in the rotational quantum number (ΔJ) between two energy levels must be ±1. This means that transitions between adjacent energy levels are allowed, while transitions between non-adjacent energy levels are not.
In the rotational spectrum of 12C16O, the energy levels are determined by the rotational quantum number J. The value of J can be any non-negative integer, with J = 0 representing the lowest energy level.
The gap between the spectral lines from J is therefore given by the difference in energy levels between two adjacent values of J. This difference can be determined using the formula:
ΔE = (h^2 / 8π^2I) * (J+1)
Where ΔE is the energy difference between two adjacent levels, h is Planck's constant, and I is the moment of inertia for the molecule.
By calculating ΔE for two adjacent values of J, you can determine the gap between the spectral lines in the rotational spectrum of 12C16O.
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The rotational spectrum of 12C16O shows the gap between the spectral lines from J"=3→4 to J" =9→10 is 24 cm-1. The rotational constant of 13C16O in cm-1 is closest toa)2.98b)0.88c)1.90d)2.08Correct answer is option 'C'. Can you explain this answer?
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The rotational spectrum of 12C16O shows the gap between the spectral lines from J"=3→4 to J" =9→10 is 24 cm-1. The rotational constant of 13C16O in cm-1 is closest toa)2.98b)0.88c)1.90d)2.08Correct answer is option 'C'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The rotational spectrum of 12C16O shows the gap between the spectral lines from J"=3→4 to J" =9→10 is 24 cm-1. The rotational constant of 13C16O in cm-1 is closest toa)2.98b)0.88c)1.90d)2.08Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The rotational spectrum of 12C16O shows the gap between the spectral lines from J"=3→4 to J" =9→10 is 24 cm-1. The rotational constant of 13C16O in cm-1 is closest toa)2.98b)0.88c)1.90d)2.08Correct answer is option 'C'. Can you explain this answer?.
The rotational spectrum of 12C16O shows the gap between the spectral lines from J"=3→4 to J" =9→10 is 24 cm-1. The rotational constant of 13C16O in cm-1 is closest toa)2.98b)0.88c)1.90d)2.08Correct answer is option 'C'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The rotational spectrum of 12C16O shows the gap between the spectral lines from J"=3→4 to J" =9→10 is 24 cm-1. The rotational constant of 13C16O in cm-1 is closest toa)2.98b)0.88c)1.90d)2.08Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The rotational spectrum of 12C16O shows the gap between the spectral lines from J"=3→4 to J" =9→10 is 24 cm-1. The rotational constant of 13C16O in cm-1 is closest toa)2.98b)0.88c)1.90d)2.08Correct answer is option 'C'. Can you explain this answer?.
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