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The number of lines exhibited by a high resolution EPR spectrum of the species, [Cu(ethylenediamine)2]2+ is [Nuclear spin (I) of Cu = 3/2 and that of N=1]
- a)12
- b)15
- c)20
- d)36
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The number of lines exhibited by a high resolution EPR spectrum of the...
The number of lines observed in the EPR spectrum is given by
2nI+1,
where n is the number of equivalent nuclei with the spin quantum number I.
The Cu2+ ion has one unpaired electron that can couple with the Cu nucleus (spin = 3/2) and one of the Nitrogen nuclei (spin = 1) in the ethylenediamine ligand.
The pattern seen in the EPR spectrum for each nucleus will be given by the formula 2I + 1, where I is the nuclear spin. For Cu (I = 3/2), we get (2(3/2) + 1) = 4 lines. For the nitrogen atom (I = 1), we get (2(1) + 1) = 3 lines.
Since the electron can independently couple with both nuclei, we need to multiply these splittings together. Therefore, considering both splittings coming from the copper and nitrogen nuclei, the resulting EPR spectrum would contain 3 * 4 = 12 lines.
However, if for each nitrogen atom (in the -NH2 units) there are three different hyperfine interactions (for each of the three protons), the EPR spectrum would contain 3 * 4 * 3= 36 lines.
So, The number of lines exhibited by a high-resolution EPR spectrum of the species, [Cu(ethylenediamine)2]2+ is 36.
2nI+1,
where n is the number of equivalent nuclei with the spin quantum number I.
The Cu2+ ion has one unpaired electron that can couple with the Cu nucleus (spin = 3/2) and one of the Nitrogen nuclei (spin = 1) in the ethylenediamine ligand.
The pattern seen in the EPR spectrum for each nucleus will be given by the formula 2I + 1, where I is the nuclear spin. For Cu (I = 3/2), we get (2(3/2) + 1) = 4 lines. For the nitrogen atom (I = 1), we get (2(1) + 1) = 3 lines.
Since the electron can independently couple with both nuclei, we need to multiply these splittings together. Therefore, considering both splittings coming from the copper and nitrogen nuclei, the resulting EPR spectrum would contain 3 * 4 = 12 lines.
However, if for each nitrogen atom (in the -NH2 units) there are three different hyperfine interactions (for each of the three protons), the EPR spectrum would contain 3 * 4 * 3= 36 lines.
So, The number of lines exhibited by a high-resolution EPR spectrum of the species, [Cu(ethylenediamine)2]2+ is 36.
Most Upvoted Answer
The number of lines exhibited by a high resolution EPR spectrum of the...
Introduction:
In electron paramagnetic resonance (EPR) spectroscopy, the number of lines observed in a spectrum is determined by the nuclear spin of the species under study. The nuclear spin value is related to the number of possible energy levels and transitions that can occur within the system. In this case, we are considering the high-resolution EPR spectrum of the species [Cu(ethylenediamine)2]2, where Cu has a nuclear spin value of 3/2 and N has a nuclear spin value of 1.
Explanation:
The number of lines exhibited by the EPR spectrum of the [Cu(ethylenediamine)2]2 complex can be determined using the formula:
Number of lines = 2I + 1
where I is the nuclear spin value.
For the Cu atom, the nuclear spin (I) is given as 3/2. Plugging this value into the formula, we get:
Number of lines for Cu = 2(3/2) + 1 = 4 + 1 = 5
For the N atom, the nuclear spin (I) is given as 1. Plugging this value into the formula, we get:
Number of lines for N = 2(1) + 1 = 2 + 1 = 3
Since the [Cu(ethylenediamine)2]2 complex contains two Cu atoms and two N atoms, we need to consider the contributions from both the Cu and N atoms.
Contributions from Cu:
Since there are two Cu atoms, the total number of lines contributed by Cu is:
Total number of lines from Cu = 2 × (Number of lines for Cu) = 2 × 5 = 10
Contributions from N:
Since there are two N atoms, the total number of lines contributed by N is:
Total number of lines from N = 2 × (Number of lines for N) = 2 × 3 = 6
Total number of lines:
Finally, we add up the contributions from Cu and N to get the total number of lines in the EPR spectrum:
Total number of lines = Total number of lines from Cu + Total number of lines from N = 10 + 6 = 16
Therefore, the correct answer is option 'D', which states that the number of lines exhibited by the high resolution EPR spectrum of [Cu(ethylenediamine)2]2 is 16.
In electron paramagnetic resonance (EPR) spectroscopy, the number of lines observed in a spectrum is determined by the nuclear spin of the species under study. The nuclear spin value is related to the number of possible energy levels and transitions that can occur within the system. In this case, we are considering the high-resolution EPR spectrum of the species [Cu(ethylenediamine)2]2, where Cu has a nuclear spin value of 3/2 and N has a nuclear spin value of 1.
Explanation:
The number of lines exhibited by the EPR spectrum of the [Cu(ethylenediamine)2]2 complex can be determined using the formula:
Number of lines = 2I + 1
where I is the nuclear spin value.
For the Cu atom, the nuclear spin (I) is given as 3/2. Plugging this value into the formula, we get:
Number of lines for Cu = 2(3/2) + 1 = 4 + 1 = 5
For the N atom, the nuclear spin (I) is given as 1. Plugging this value into the formula, we get:
Number of lines for N = 2(1) + 1 = 2 + 1 = 3
Since the [Cu(ethylenediamine)2]2 complex contains two Cu atoms and two N atoms, we need to consider the contributions from both the Cu and N atoms.
Contributions from Cu:
Since there are two Cu atoms, the total number of lines contributed by Cu is:
Total number of lines from Cu = 2 × (Number of lines for Cu) = 2 × 5 = 10
Contributions from N:
Since there are two N atoms, the total number of lines contributed by N is:
Total number of lines from N = 2 × (Number of lines for N) = 2 × 3 = 6
Total number of lines:
Finally, we add up the contributions from Cu and N to get the total number of lines in the EPR spectrum:
Total number of lines = Total number of lines from Cu + Total number of lines from N = 10 + 6 = 16
Therefore, the correct answer is option 'D', which states that the number of lines exhibited by the high resolution EPR spectrum of [Cu(ethylenediamine)2]2 is 16.
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The number of lines exhibited by a high resolution EPR spectrum of the species,[Cu(ethylenediamine)2]2+is [Nuclear spin (I) of Cu = 3/2 and that of N=1]a)12b)15c)20d)36Correct answer is option 'D'. Can you explain this answer?
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The number of lines exhibited by a high resolution EPR spectrum of the species,[Cu(ethylenediamine)2]2+is [Nuclear spin (I) of Cu = 3/2 and that of N=1]a)12b)15c)20d)36Correct answer is option 'D'. Can you explain this answer? for UGC NET 2025 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The number of lines exhibited by a high resolution EPR spectrum of the species,[Cu(ethylenediamine)2]2+is [Nuclear spin (I) of Cu = 3/2 and that of N=1]a)12b)15c)20d)36Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for UGC NET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The number of lines exhibited by a high resolution EPR spectrum of the species,[Cu(ethylenediamine)2]2+is [Nuclear spin (I) of Cu = 3/2 and that of N=1]a)12b)15c)20d)36Correct answer is option 'D'. Can you explain this answer?.
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