UGC NET Exam > UGC NET Questions > The initial rate of a first-order reaction be...
Start Learning for Free
The initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K. If the half-life time of the reaction at 400K is 10 min, The time needed for 19% completion of the reaction at 420K will be (up to two decimal places)
- a)81.01 sec
- b)54.65 sec
- c)60.98 sec
- d)90.02 sec
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The initial rate of a first-order reaction becomes three times when th...
Given data:
- Initial rate at 400K = k
- Initial rate at 420K = 3k
- Half-life time at 400K = 10 min
Calculating rate constant:
- For a first-order reaction, the rate constant (k) is inversely proportional to the half-life time.
- Using the half-life time formula for first-order reactions: ln(2) / k = 10 min
- Solving for k: k = ln(2) / 10 min ≈ 0.0693 min^-1
Calculating time for 19% completion at 420K:
- The integrated rate law for first-order reactions is: ln([A]₀/[A]t) = kt
- At 420K, the rate constant k = 3k = 3 * 0.0693 ≈ 0.2079 min^-1
- The time needed for 19% completion can be found by setting [A]t = 0.81[A]₀ (19% completion) and solving for t:
ln(1/0.81) = 0.2079t
t = ln(1/0.81) / 0.2079 ≈ 60.98 sec
Therefore, the time needed for 19% completion of the reaction at 420K will be approximately 60.98 seconds. Hence, option C is the correct answer.
Free Test
FREE
| Start Free Test |
Community Answer
The initial rate of a first-order reaction becomes three times when th...
At, 400 K the time required for 50% completion of the reaction is 10 min.
= 1.155 × 10-3 sec-1
= 1.155 × 10-3 sec-1
- Again, the initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K.
- Thus,
= 3 × 1.155 × 10-3 sec-1
= 3.456 × 10-3 sec-1 - The time required for 19% completion of the reaction at 420K is,
= 60.98 sec
Hence, the time needed for 19% completion of the reaction at 420K will be 60.98 sec.
Attention UGC NET Students!
To make sure you are not studying endlessly, EduRev has designed UGC NET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UGC NET.
|
Explore Courses for UGC NET exam
|
|
Similar UGC NET Doubts
Top Courses for UGC NETView all
The initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K. If the half-life time of the reaction at 400K is 10 min, The time needed for 19% completion of the reaction at 420K will be (up to two decimal places)a)81.01 secb)54.65 secc)60.98 secd)90.02 secCorrect answer is option 'C'. Can you explain this answer?
Question Description
The initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K. If the half-life time of the reaction at 400K is 10 min, The time needed for 19% completion of the reaction at 420K will be (up to two decimal places)a)81.01 secb)54.65 secc)60.98 secd)90.02 secCorrect answer is option 'C'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K. If the half-life time of the reaction at 400K is 10 min, The time needed for 19% completion of the reaction at 420K will be (up to two decimal places)a)81.01 secb)54.65 secc)60.98 secd)90.02 secCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K. If the half-life time of the reaction at 400K is 10 min, The time needed for 19% completion of the reaction at 420K will be (up to two decimal places)a)81.01 secb)54.65 secc)60.98 secd)90.02 secCorrect answer is option 'C'. Can you explain this answer?.
The initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K. If the half-life time of the reaction at 400K is 10 min, The time needed for 19% completion of the reaction at 420K will be (up to two decimal places)a)81.01 secb)54.65 secc)60.98 secd)90.02 secCorrect answer is option 'C'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K. If the half-life time of the reaction at 400K is 10 min, The time needed for 19% completion of the reaction at 420K will be (up to two decimal places)a)81.01 secb)54.65 secc)60.98 secd)90.02 secCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K. If the half-life time of the reaction at 400K is 10 min, The time needed for 19% completion of the reaction at 420K will be (up to two decimal places)a)81.01 secb)54.65 secc)60.98 secd)90.02 secCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K. If the half-life time of the reaction at 400K is 10 min, The time needed for 19% completion of the reaction at 420K will be (up to two decimal places)a)81.01 secb)54.65 secc)60.98 secd)90.02 secCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for UGC NET.
Download more important topics, notes, lectures and mock test series for UGC NET Exam by signing up for free.
Here you can find the meaning of The initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K. If the half-life time of the reaction at 400K is 10 min, The time needed for 19% completion of the reaction at 420K will be (up to two decimal places)a)81.01 secb)54.65 secc)60.98 secd)90.02 secCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K. If the half-life time of the reaction at 400K is 10 min, The time needed for 19% completion of the reaction at 420K will be (up to two decimal places)a)81.01 secb)54.65 secc)60.98 secd)90.02 secCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for The initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K. If the half-life time of the reaction at 400K is 10 min, The time needed for 19% completion of the reaction at 420K will be (up to two decimal places)a)81.01 secb)54.65 secc)60.98 secd)90.02 secCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of The initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K. If the half-life time of the reaction at 400K is 10 min, The time needed for 19% completion of the reaction at 420K will be (up to two decimal places)a)81.01 secb)54.65 secc)60.98 secd)90.02 secCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The initial rate of a first-order reaction becomes three times when the temperature increases from 400K to 420K. If the half-life time of the reaction at 400K is 10 min, The time needed for 19% completion of the reaction at 420K will be (up to two decimal places)a)81.01 secb)54.65 secc)60.98 secd)90.02 secCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice UGC NET tests.
|
|
Explore Courses for UGC NET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup