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What is the order of decreasing carbonyl stretching frequencies in the following species (A - D)?
A. [Mn(CO)6]+
B. [Os(CO)6]2+
C. [Ir(CO)6]3+
D. Free CO
A. [Mn(CO)6]+
B. [Os(CO)6]2+
C. [Ir(CO)6]3+
D. Free CO
- a)B > A > C > D
- b)D > C > B > A
- c)A > B > C > D
- d)C > B > D > A
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
What is the order of decreasing carbonyl stretching frequencies in the...
A. [Mn(CO)6]+:
- In the complex [Mn(CO)6]+, there is a positive charge on the metal atom and six (CO) ligand.
- As there is no negative charge on the metal for the delocalization with the carbonyl (CO) group, the CO stretching frequency will be higher in the complex Mn(CO)6+
B. [Os(CO)6]2+:
- In the complex [Os(CO)6]2+, there is two positive charge on the metal atom and six CO ligands.
- Due to the presence of two positive charges, the extent of metal-ligand back donation is low.
- Thus, the CO stretching frequency in [Os(CO)6]2+ will be higher than the complex Mn(CO)6+
C. [Ir(CO)6]3+:
- In the complex [Ir(CO)6]3+, there are three positive charges on the metal atom and six CO ligands.
- Due to the presence of three positive charges, the extent of metal-ligand back donation is the lowest.
- Thus, the CO stretching frequency in [Ir(CO)6]3+ will be highest among all the complexes.
D. Free CO:
- In the free CO, the CO stretching frequency will be more than [Mn(CO)6]+
Hence, the order of decreasing carbonyl stretching frequencies is C > B > D > A
Most Upvoted Answer
What is the order of decreasing carbonyl stretching frequencies in the...
Carbonyl stretching frequencies in the given species:
Order of decreasing frequencies:
- C.[Ir(CO)6]3+
- B.[Os(CO)6]2+
- D. Free CO
- A.[Mn(CO)6]+
Explanation:
- The order of decreasing carbonyl stretching frequencies is determined by the strength of the metal-carbonyl bond.
- In this case, the metal ions in C, B, and D are in the +3, +2, and 0 oxidation states, respectively.
- The higher the oxidation state of the metal ion, the stronger the metal-carbonyl bond, leading to a higher stretching frequency.
- Therefore, the carbonyl stretching frequency is highest for [Ir(CO)6]3+, followed by [Os(CO)6]2+, Free CO, and [Mn(CO)6]+ in decreasing order.
By following the above logic, we can conclude that the correct order of decreasing carbonyl stretching frequencies in the given species is:
C > B > D > A.
Order of decreasing frequencies:
- C.[Ir(CO)6]3+
- B.[Os(CO)6]2+
- D. Free CO
- A.[Mn(CO)6]+
Explanation:
- The order of decreasing carbonyl stretching frequencies is determined by the strength of the metal-carbonyl bond.
- In this case, the metal ions in C, B, and D are in the +3, +2, and 0 oxidation states, respectively.
- The higher the oxidation state of the metal ion, the stronger the metal-carbonyl bond, leading to a higher stretching frequency.
- Therefore, the carbonyl stretching frequency is highest for [Ir(CO)6]3+, followed by [Os(CO)6]2+, Free CO, and [Mn(CO)6]+ in decreasing order.
By following the above logic, we can conclude that the correct order of decreasing carbonyl stretching frequencies in the given species is:
C > B > D > A.
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