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A one-component system with the associated phase diagram (see the figure) is not possible because 
  • a)
    OB has a negative slops 
  • b)
    OC has a positive slope
  • c)
    Both OB and OC are linear
  • d)
    OB, OC and OD cannot all coexist, given OA
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
A one-component system with the associated phase diagram (see the figu...
In a one-component system (also known as a unary system), four phases cannot simultaneously exist at a single point under typical conditions. The reason for this lies in the phase diagrams and the thermodynamic constraints governing phase equilibria.
A one-component system typically consists of a single substance, and the number of phases that can coexist at a specific point in its phase diagram is restricted by the Gibbs phase rule. The Gibbs phase rule states:
F = C - P + 2
Where:
F = Degrees of freedom (the number of intensive variables that can be independently varied while maintaining phase equilibrium)
C = Number of components in the system
P = Number of phases in the system
For a one-component system (C = 1), the Gibbs phase rule simplifies to:
F = 3 - P
Now, let's consider the possible number of phases (P) and degrees of freedom (F) under various conditions:
Single Phase (P = 1): If there is only one phase, F = 3 - 1 = 2. This means you have two degrees of freedom to change temperature and pressure while maintaining the single-phase equilibrium.
Two Phases (P = 2): When two phases coexist, F = 3 - 2 = 1. This means you have one degree of freedom, typically pressure, to vary while keeping both phases in equilibrium.
Three Phases (P = 3): When three phases coexist, F = 3 - 3 = 0. This indicates that there are no degrees of freedom, and the system is at a unique equilibrium point with fixed temperature and pressure.
Four or More Phases (P ≥ 4): When you attempt to have four or more phases simultaneously, F becomes negative, which is thermodynamically prohibited under typical conditions.
This means that in a one-component system, it is not possible to have four phases in equilibrium at a single point under standard conditions.
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A one-component system with the associated phase diagram (see the figure) is not possible becausea)OB has a negative slopsb)OC has a positive slopec)Both OB and OC are lineard)OB, OC and OD cannot all coexist, given OACorrect answer is option 'D'. Can you explain this answer?
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