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Repeated measurements of Pb in a lake water sample gave 3.2, 5.2, and 7.2 ppb of Pb. The standard deviation in the measurement of Pb is
  • a)
    2 ppb
  • b)
    4 ppb
  • c)
    0 ppb
  • d)
    2√2 ppb
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Repeated measurements of Pb in a lake water sample gave 3.2, 5.2, and ...
B) 4 ppb

To calculate the standard deviation, first find the mean of the measurements:
(3.2 + 5.2 + 7.2) / 3 = 5.2 ppb

Next, calculate the differences between each measurement and the mean, square each difference, sum the squared differences, divide by n-1, and then take the square root:
[(3.2-5.2)^2 + (5.2-5.2)^2 + (7.2-5.2)^2] / 2 = 4 ppb

Therefore, the standard deviation in the measurement of Pb is 4 ppb.
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Community Answer
Repeated measurements of Pb in a lake water sample gave 3.2, 5.2, and ...
The repeated measurements of Pb in a lake water sample gave 3.2, 5.2, and 7.2 ppb of Pb.
so, x1 = 3.2, x2 = 5.2, x3 = 7.2
Thus, The mean (x̄) value will be

N = Total number of Terms
= 3
Now, standard deviation (s) will ne

= 2 ppb
Hence, the standard deviation in the measurement of Pb is 2 ppb.
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Repeated measurements of Pb in a lake water sample gave 3.2, 5.2, and 7.2 ppb of Pb. The standard deviation in the measurement of Pb isa)2 ppbb)4 ppbc)0 ppbd)2√2 ppbCorrect answer is option 'A'. Can you explain this answer?
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