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Can you explain the answer of this question below:
The position of a particle at time 't' is given by the relation
x(t) = 
where V0 is a constant and a > 0. The dimensions of V0 and a are respectively.
  • A:
    M0L1T0 and T_1
  • B:
    M0L1T0 and T_2
  • C:
    M0L1T_1 and T_1
  • D:
    M0L1T_1 and T_2
The answer is C.
Verified Answer
Can you explain the answer of this question below:The position of a pa...
Given, 
x = v0/a (1 - e^-at) 
The term r is dimensionless. Therefore, at must be dimensionless, i.e. [M^0 L^0 T^0]. 
Since, t has the dimension of time, i.e., [M^0 L^0 T1] 
So, the dimension of a must be [M^0L^0 T^-1] 

Again, 
vo/a must have the dimension of distance. i.e. [M^0 L^1 T^0] 
Since, the dimension of a is [M^0 L^0 T^-1]
The dimension of v0 must be [M^0 L^1 T^-1]
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Can you explain the answer of this question below:The position of a pa...
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Can you explain the answer of this question below:The position of a pa...
Solution suppose that at=1 then the dimension of a=1/t x=v/1/t , L×1/t that is answer c is correct
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Can you explain the answer of this question below:The position of a particle at time 't' is given by the relationx(t) =where V0is a constant and a > 0. The dimensions of V0and a are respectively.A:M0L1T0and T_1B:M0L1T0and T_2C:M0L1T_1and T_1D:M0L1T_1and T_2The answer is C.
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