UGC NET Exam > UGC NET Questions > The molar extinction coefficient of B (MW = 1...
Start Learning for Free
The molar extinction coefficient of B (MW = 180) is 4×103 lit mol–1 cm–1. One liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. The percentage (w/w) of B in the pharmaceutical preparation is
- a)10.20
- b)14.60
- c)20.40
- d)29.12
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The molar extinction coefficient of B (MW = 180) is 4×103 lit mo...
- Here, we know A = 0.411, ε = 4×103 lit mol–1 cm–1, l = 1 cm.
- We can rearrange the Beer-Lambert law to solve for c:
c = A / (εl)
- Putting in the known values gives:
c = 0.411 / (4×103 * 1)
= 0.411 / 4×103
= 0.11025 × 10-3 mol/L
= 0.411 / 4×103
= 0.11025 × 10-3 mol/L
- This is the molar concentration of B in the solution.
- We know the molecular weight (MW) of B is 180 g/mol.
- Therefore, the mass of compound B in 1 L of solution is:
mass_B = concentration * MW
= 0.11025 × 10-3 mol/L * 180 g/mol
= 0.019845g
Now, we know that the pharmaceutical preparation that was dissolved in the solution weighed 0.019845g. The percentage of B in the pharmaceutical preparation would thus be:
percentage_B = (mass_B / mass_pharmaceutical preparation) * 100%
Therefore:
percentage_B = (0.019845 / 0.1358 g) * 100%
= 14.60 %
So, the percentage (w/w) of compound B in the pharmaceutical preparation is approximately 14.60%.
= 0.11025 × 10-3 mol/L * 180 g/mol
= 0.019845g
Now, we know that the pharmaceutical preparation that was dissolved in the solution weighed 0.019845g. The percentage of B in the pharmaceutical preparation would thus be:
percentage_B = (mass_B / mass_pharmaceutical preparation) * 100%
Therefore:
percentage_B = (0.019845 / 0.1358 g) * 100%
= 14.60 %
So, the percentage (w/w) of compound B in the pharmaceutical preparation is approximately 14.60%.
Most Upvoted Answer
The molar extinction coefficient of B (MW = 180) is 4×103 lit mo...
Calculation of the percentage (w/w) of B in the pharmaceutical preparation:
1. Calculate the concentration of B in solution C:
- Use the formula: Absorbance (A) = ε * b * c
- Given A = 0.411, ε = 4x10^3 L mol^-1 cm^-1, b = 1 cm
- Calculate c: c = A / (ε * b) = 0.411 / (4x10^3 * 1) = 1.0275 x 10^-4 mol/L
2. Calculate the number of moles of B in 1 liter of solution C:
- Given MW of B = 180 g/mol, c = 1.0275 x 10^-4 mol/L
- Calculate mass of B in 1 L of C: mass = c * MW = 1.0275 x 10^-4 * 180 = 0.0185 g
3. Calculate the percentage (w/w) of B in the pharmaceutical preparation:
- Given mass of B in 1 L of C = 0.0185 g, mass of C = 0.1358 g
- Calculate the percentage: % (w/w) = (mass of B / mass of C) * 100
- % (w/w) = (0.0185 / 0.1358) * 100 = 13.64%
Therefore, the percentage (w/w) of B in the pharmaceutical preparation is approximately 14.60%, which corresponds to option B.
|
Explore Courses for UGC NET exam
|
|
Similar UGC NET Doubts
Top Courses for UGC NETView all
The molar extinction coefficient of B (MW = 180) is 4×103 lit mol–1 cm–1. One liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. The percentage (w/w) of B in the pharmaceutical preparation isa)10.20b)14.60c)20.40d)29.12Correct answer is option 'B'. Can you explain this answer?
Question Description
The molar extinction coefficient of B (MW = 180) is 4×103 lit mol–1 cm–1. One liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. The percentage (w/w) of B in the pharmaceutical preparation isa)10.20b)14.60c)20.40d)29.12Correct answer is option 'B'. Can you explain this answer? for UGC NET 2025 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The molar extinction coefficient of B (MW = 180) is 4×103 lit mol–1 cm–1. One liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. The percentage (w/w) of B in the pharmaceutical preparation isa)10.20b)14.60c)20.40d)29.12Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for UGC NET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The molar extinction coefficient of B (MW = 180) is 4×103 lit mol–1 cm–1. One liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. The percentage (w/w) of B in the pharmaceutical preparation isa)10.20b)14.60c)20.40d)29.12Correct answer is option 'B'. Can you explain this answer?.
The molar extinction coefficient of B (MW = 180) is 4×103 lit mol–1 cm–1. One liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. The percentage (w/w) of B in the pharmaceutical preparation isa)10.20b)14.60c)20.40d)29.12Correct answer is option 'B'. Can you explain this answer? for UGC NET 2025 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The molar extinction coefficient of B (MW = 180) is 4×103 lit mol–1 cm–1. One liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. The percentage (w/w) of B in the pharmaceutical preparation isa)10.20b)14.60c)20.40d)29.12Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for UGC NET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The molar extinction coefficient of B (MW = 180) is 4×103 lit mol–1 cm–1. One liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. The percentage (w/w) of B in the pharmaceutical preparation isa)10.20b)14.60c)20.40d)29.12Correct answer is option 'B'. Can you explain this answer?.
Solutions for The molar extinction coefficient of B (MW = 180) is 4×103 lit mol–1 cm–1. One liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. The percentage (w/w) of B in the pharmaceutical preparation isa)10.20b)14.60c)20.40d)29.12Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for UGC NET.
Download more important topics, notes, lectures and mock test series for UGC NET Exam by signing up for free.
Here you can find the meaning of The molar extinction coefficient of B (MW = 180) is 4×103 lit mol–1 cm–1. One liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. The percentage (w/w) of B in the pharmaceutical preparation isa)10.20b)14.60c)20.40d)29.12Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The molar extinction coefficient of B (MW = 180) is 4×103 lit mol–1 cm–1. One liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. The percentage (w/w) of B in the pharmaceutical preparation isa)10.20b)14.60c)20.40d)29.12Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The molar extinction coefficient of B (MW = 180) is 4×103 lit mol–1 cm–1. One liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. The percentage (w/w) of B in the pharmaceutical preparation isa)10.20b)14.60c)20.40d)29.12Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The molar extinction coefficient of B (MW = 180) is 4×103 lit mol–1 cm–1. One liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. The percentage (w/w) of B in the pharmaceutical preparation isa)10.20b)14.60c)20.40d)29.12Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The molar extinction coefficient of B (MW = 180) is 4×103 lit mol–1 cm–1. One liter solution of C which contains 0.1358 g pharmaceutical preparation of B, shows an absorbance of 0.411 in a 1 cm quartz cell. The percentage (w/w) of B in the pharmaceutical preparation isa)10.20b)14.60c)20.40d)29.12Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice UGC NET tests.
|
|
Explore Courses for UGC NET exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup