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The electronic spectrum of [Ti(H2O)6]3+shows a single broad peak with a maximum at 20,300 cm-1. The crystal field stabilisation energy (CFSE) of the complex ion, in kJ mol-1, is (1 kJ mol-1= 83.7 cm-1)a)145.5b)97c)242.5d)83.7Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about The electronic spectrum of [Ti(H2O)6]3+shows a single broad peak with a maximum at 20,300 cm-1. The crystal field stabilisation energy (CFSE) of the complex ion, in kJ mol-1, is (1 kJ mol-1= 83.7 cm-1)a)145.5b)97c)242.5d)83.7Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam.
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The electronic spectrum of [Ti(H2O)6]3+shows a single broad peak with a maximum at 20,300 cm-1. The crystal field stabilisation energy (CFSE) of the complex ion, in kJ mol-1, is (1 kJ mol-1= 83.7 cm-1)a)145.5b)97c)242.5d)83.7Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The electronic spectrum of [Ti(H2O)6]3+shows a single broad peak with a maximum at 20,300 cm-1. The crystal field stabilisation energy (CFSE) of the complex ion, in kJ mol-1, is (1 kJ mol-1= 83.7 cm-1)a)145.5b)97c)242.5d)83.7Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The electronic spectrum of [Ti(H2O)6]3+shows a single broad peak with a maximum at 20,300 cm-1. The crystal field stabilisation energy (CFSE) of the complex ion, in kJ mol-1, is (1 kJ mol-1= 83.7 cm-1)a)145.5b)97c)242.5d)83.7Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The electronic spectrum of [Ti(H2O)6]3+shows a single broad peak with a maximum at 20,300 cm-1. The crystal field stabilisation energy (CFSE) of the complex ion, in kJ mol-1, is (1 kJ mol-1= 83.7 cm-1)a)145.5b)97c)242.5d)83.7Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.