Which of the following is the correct statement regarding the nitrogen...
Nitrogen in pyridine has sp2 hybridization because the lone pair of electron present on it is involved in delocalization.
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Which of the following is the correct statement regarding the nitrogen...
Explanation:
- Hybridization of Nitrogen in Pyridine:
Pyridine is a heterocyclic aromatic compound which contains a nitrogen atom in its ring structure. The nitrogen in pyridine is sp2 hybridized.
- Reason for sp2 hybridization:
The nitrogen atom in pyridine has three sigma bonds with the three carbon atoms in the ring. In order to form these three sigma bonds, the nitrogen atom undergoes sp2 hybridization. This allows the nitrogen atom to form three bonds in a trigonal planar geometry.
- Structure of Pyridine:
In the case of pyridine, the nitrogen atom is part of a six-membered ring system, and its sp2 hybridization is essential for maintaining the planarity of the molecule. The presence of the lone pair on the nitrogen atom contributes to the aromatic character of pyridine.
- Comparison with other hybridization states:
If the nitrogen atom in pyridine were to be sp hybridized, it would only be able to form two sigma bonds, which is not consistent with the observed structure of pyridine. Similarly, if it were sp3 hybridized, it would have formed four sigma bonds, which is also not in line with the actual bonding pattern in pyridine.
Therefore, the correct statement regarding the nitrogen in pyridine is that it is sp2 hybridized, which allows it to form three sigma bonds in a trigonal planar geometry within the aromatic ring structure.