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Can you explain the answer of this question below:
An ant moves from one corner of a hall to the diagonally opposite corner. If the dimension of the hall are 8 m x 6 m, the displacement of the ant is :
- A:10 m
- B:14 m
- C:28m
- D:2 m
The answer is a.
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Verified Answer
Can you explain the answer of this question below:An ant moves from on...
In this case
Displacement = hypotenuse
Displacement = (8^2 +6^2 )^1/2 = 10 m
Most Upvoted Answer
Can you explain the answer of this question below:An ant moves from on...
(h)²=(p)²+(b)²= (h)²=(8m)²+(6m)²= (h)²=(64+36)m²= (h)²=100m²= h=√10m²= h=10 m Answer?
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Can you explain the answer of this question below:An ant moves from on...
Given:
Dimensions of hall = 8 m x 6 m
To find:
Displacement of the ant
Solution:
We can use the Pythagorean theorem to find the displacement of the ant. According to the theorem, in a right-angled triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
Let us consider the hall as a rectangle ABCD, where AB = 8 m and BC = 6 m. The ant moves from A to C, which is the diagonally opposite corner.
We can draw a right-angled triangle ACD, where AC is the hypotenuse, AD is one side (which is equal to AB), and CD is the other side (which is equal to BC).
Using the Pythagorean theorem, we have:
AC^2 = AD^2 + CD^2
Substituting the values, we get:
AC^2 = 8^2 + 6^2
AC^2 = 64 + 36
AC^2 = 100
AC = √100
AC = 10 m
Therefore, the displacement of the ant is 10 m.
Answer:
a) 10 m
Dimensions of hall = 8 m x 6 m
To find:
Displacement of the ant
Solution:
We can use the Pythagorean theorem to find the displacement of the ant. According to the theorem, in a right-angled triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
Let us consider the hall as a rectangle ABCD, where AB = 8 m and BC = 6 m. The ant moves from A to C, which is the diagonally opposite corner.
We can draw a right-angled triangle ACD, where AC is the hypotenuse, AD is one side (which is equal to AB), and CD is the other side (which is equal to BC).
Using the Pythagorean theorem, we have:
AC^2 = AD^2 + CD^2
Substituting the values, we get:
AC^2 = 8^2 + 6^2
AC^2 = 64 + 36
AC^2 = 100
AC = √100
AC = 10 m
Therefore, the displacement of the ant is 10 m.
Answer:
a) 10 m
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Can you explain the answer of this question below:An ant moves from one corner of a hall to the diagonally opposite corner. If the dimension of the hall are 8 m x 6 m, the displacement of the ant is :A:10 mB:14 mC:28mD:2 mThe answer is a.
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