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Train X and train Y pass one another traveling in opposite directions. Forty minutes later they are 100 miles apart. If train X’s constant speed is 30 miles per hour greater than train Y’s, how far does train X travel during that time?
  • a)
    28
  • b)
    40
  • c)
    60
  • d)
    72
  • e)
    80
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Train X and train Y pass one another traveling in opposite directions....
Is traveling at a constant speed of 60 miles per hour, we can calculate the speed of train Y.

Let's assume the speed of train Y is "Y" miles per hour.

Since train X and train Y are traveling in opposite directions, their speeds will add up when calculating the distance covered in 40 minutes.

Train X covers a distance of 60 miles per hour * (40 minutes / 60 minutes per hour) = 40 miles in 40 minutes.

Train Y covers a distance of Y miles per hour * (40 minutes / 60 minutes per hour) = (2/3)Y miles in 40 minutes.

Since the total distance covered by both trains is 100 miles, we can write the equation:

40 miles + (2/3)Y miles = 100 miles

To solve for Y, we subtract 40 miles from both sides of the equation:

(2/3)Y miles = 100 miles - 40 miles

(2/3)Y miles = 60 miles

Next, we multiply both sides of the equation by 3/2 to isolate Y:

Y miles = (60 miles) * (3/2)

Y miles = 90 miles

Therefore, train Y is traveling at a speed of 90 miles per hour.
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