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Can you explain the answer of this question below:
The speed of overtaking and overtaken vehicles are 90 Kmph and 72 Kmph respectively. Calculate the overtaking sight distance. Assume acceleration of overtaking vehicle as 0.8 m/s2 and traffic stream moves in one way.
  • A:
    230 m
  • B:
    280 m
  • C:
    480 m
  • D:
    530 m
The answer is B.
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Can you explain the answer of this question below:The speed of overtak...
OSD for two traffic = d1+d2+d3 Assuming design speed as the speed of overtaking vehicle , V=70kmph v=70/3.6 =19.4m/sec vb =40/3.6 = 11.1m/sec D1 = vb t =11.1*2 = 22.2m D2 = vb *T+2s S=(0.7 vb +6) =(0.7*11.1+6) =13.8m T = =√ (4*13.8/0.99) =7.47sec D2= 11.1 * 7.47 +2*13.8 =110.5m D3 =v.T =194*7.47 =144.9m OSD = 22.2 +110.5 +14409 =277.6m
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Can you explain the answer of this question below:The speed of overtaking andovertaken vehicles are 90 Kmph and72 Kmph respectively. Calculatethe overtaking sight distance.Assume acceleration of overtakingvehicle as 0.8 m/s2 and trafficstream moves in one way.A:230 mB:280 mC:480 mD:530 mThe answer is B.
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Can you explain the answer of this question below:The speed of overtaking andovertaken vehicles are 90 Kmph and72 Kmph respectively. Calculatethe overtaking sight distance.Assume acceleration of overtakingvehicle as 0.8 m/s2 and trafficstream moves in one way.A:230 mB:280 mC:480 mD:530 mThe answer is B. for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Can you explain the answer of this question below:The speed of overtaking andovertaken vehicles are 90 Kmph and72 Kmph respectively. Calculatethe overtaking sight distance.Assume acceleration of overtakingvehicle as 0.8 m/s2 and trafficstream moves in one way.A:230 mB:280 mC:480 mD:530 mThe answer is B. covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Can you explain the answer of this question below:The speed of overtaking andovertaken vehicles are 90 Kmph and72 Kmph respectively. Calculatethe overtaking sight distance.Assume acceleration of overtakingvehicle as 0.8 m/s2 and trafficstream moves in one way.A:230 mB:280 mC:480 mD:530 mThe answer is B..
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