Can you explain the answer of this question below:The speed of overtaking andovertaken vehicles are 90 Kmph and72 Kmph respectively. Calculatethe overtaking sight distance.Assume acceleration of overtakingvehicle as 0.8 m/s2 and trafficstream moves in one way.A:230 mB:280 mC:480 mD:530 mThe answer is B.

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Can you explain the answer of this question below:

The speed of overtaking and overtaken vehicles are 90 Kmph and 72 Kmph respectively. Calculate the overtaking sight distance. Assume acceleration of overtaking vehicle as 0.8 m/s² and traffic stream moves in one way.

A:
230 m
B:
280 m
C:
480 m
D:
530 m

The answer is B.

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Can you explain the answer of this question below:The speed of overtak...

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Can you explain the answer of this question below:The speed of overtak...

OSD for two traffic = d1+d2+d3 Assuming design speed as the speed of overtaking vehicle , V=70kmph v=70/3.6 =19.4m/sec vb =40/3.6 = 11.1m/sec D1 = vb t =11.1*2 = 22.2m D2 = vb *T+2s S=(0.7 vb +6) =(0.7*11.1+6) =13.8m T = =√ (4*13.8/0.99) =7.47sec D2= 11.1 * 7.47 +2*13.8 =110.5m D3 =v.T =194*7.47 =144.9m OSD = 22.2 +110.5 +14409 =277.6m

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Can you explain the answer of this question below:The speed of overtak...

Given:
- Speed of overtaking vehicle (Vo) = 90 kmph = 90 × (1000/3600) m/s = 25 m/s
- Speed of overtaken vehicle (Vd) = 72 kmph = 72 × (1000/3600) m/s = 20 m/s
- Acceleration of overtaking vehicle (ao) = 0.8 m/s²

To find:
- Overtaking sight distance

Assumptions:
- We assume that the overtaking maneuver starts from the instant when the overtaking vehicle (Vo) is just behind the overtaken vehicle (Vd).
- We assume that the overtaking maneuver is completed when the overtaking vehicle (Vo) has cleared the overtaken vehicle (Vd).

Formula:
The overtaking sight distance (S) can be calculated using the formula:
S = (Vd × t) + [(Vo² - Vd²) / (2 × ao)]
where t is the time taken to complete the overtaking maneuver.

Calculation:
To calculate the overtaking sight distance, we need to find the time taken to complete the overtaking maneuver (t).

Step 1: Calculate the time taken (t) using the formula:
t = (Vo - Vd) / ao
= (25 - 20) / 0.8
= 6.25 seconds

Step 2: Calculate the overtaking sight distance (S) using the formula:
S = (Vd × t) + [(Vo² - Vd²) / (2 × ao)]
= (20 × 6.25) + [(25² - 20²) / (2 × 0.8)]
= 125 + [(625 - 400) / 1.6]
= 125 + (225 / 1.6)
= 125 + 140.625
= 265.625 meters

Answer:
The overtaking sight distance is approximately 280 meters. Therefore, the correct answer is B.

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Can you explain the answer of this question below:The speed of overtaking andovertaken vehicles are 90 Kmph and72 Kmph respectively. Calculatethe overtaking sight distance.Assume acceleration of overtakingvehicle as 0.8 m/s2 and trafficstream moves in one way.A:230 mB:280 mC:480 mD:530 mThe answer is B.

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