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Can you explain the answer of this question below:
The angular position of a particle (in radians), along a circle of radius 0.8 m is given by the function in time (seconds) by 
. The linear velocity of the particle
. The linear velocity of the particle- A:1.84 m/s
- B:1.80 m/s
- C:1.82 m/s
- D:1.88 m/s
The answer is a.
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Verified Answer
Can you explain the answer of this question below:The angular position...
The answer is option A
So, as we know,
After differentiating angular velocity with respect to t,
Linear velocity=2t+2.3=ω
Now,
Velocity=r x ω(where r is 0.8m)
=0.8x2.3
=1.84m/s
So, as we know,
After differentiating angular velocity with respect to t,
Linear velocity=2t+2.3=ω
Now,
Velocity=r x ω(where r is 0.8m)
=0.8x2.3
=1.84m/s
Most Upvoted Answer
Can you explain the answer of this question below:The angular position...
Linear velocity = radius × angular velocityv= r× omega =0.8× t^2 + 2.3t+1=0.8× 2.3=1.84m/s
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Community Answer
Can you explain the answer of this question below:The angular position...
First step ,
linear velocity = radius × angular velocity
second step,
angular displacement = t^2+2.3t+1 ko differentiation karna ho with respect to t
then angular velo. = 2t+2.3 =omega
third step ,
velocity = r × omega. ( r = 0.8)
velo. = 1.84 m/s
linear velocity = radius × angular velocity
second step,
angular displacement = t^2+2.3t+1 ko differentiation karna ho with respect to t
then angular velo. = 2t+2.3 =omega
third step ,
velocity = r × omega. ( r = 0.8)
velo. = 1.84 m/s
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Can you explain the answer of this question below:The angular position of a particle (in radians), along a circle of radius 0.8 m is given by the function in time (seconds) by. The linear velocity of the particleA:1.84 m/sB:1.80 m/sC:1.82 m/sD:1.88 m/sThe answer is a.
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