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A person works along the line A'B' of the large 10 M wide plan moving at 2 m per second in a direction parallel to the length of the reaching the opposite its he germs on to the ground to arrive at point see that lies on the man move set 2 m per second on the plank with respect to it A. The time taken by man to cross the plank is 5 seconds B. The distance between the points B and C is 10 m C. The absolute velocity of man is 2√2 m per second D. All the above are correct?
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A person works along the line A'B' of the large 10 M wide plan moving ...
Explanation:
To solve this problem, we need to consider the motion of the person on the plank and their relative motion with respect to the ground.
Relative Motion on the Plank:
The person is moving along the line A'B' of the plank with a velocity of 2 m/s. The distance between points A and B is 10 m. Therefore, the time taken by the person to cross the plank is given by:
Time = Distance / Velocity
Time = 10 m / 2 m/s
Time = 5 s
So, statement A is correct.
Distance between Points B and C:
The person reaches point C on the ground after crossing the plank. The distance between points B and C can be determined using the Pythagorean theorem:
BC^2 = AB^2 + AC^2
BC^2 = (10 m)^2 + (10 m)^2
BC^2 = 100 m^2 + 100 m^2
BC^2 = 200 m^2
BC = √(200 m^2)
BC = 10√2 m
So, statement B is correct.
Absolute Velocity of the Person:
The absolute velocity of the person is the velocity with respect to the ground. Since the person is moving at a constant velocity of 2 m/s on the plank, and the plank itself is moving at a velocity of 2 m/s with respect to the ground, the absolute velocity of the person is the vector sum of these velocities. Using the principle of vector addition, we can determine the absolute velocity as follows:
Absolute Velocity = √(Velocity on the Plank^2 + Velocity of the Plank^2)
Absolute Velocity = √((2 m/s)^2 + (2 m/s)^2)
Absolute Velocity = √(4 m^2/s^2 + 4 m^2/s^2)
Absolute Velocity = √(8 m^2/s^2)
Absolute Velocity = 2√2 m/s
So, statement C is correct.
Therefore, all the statements A, B, and C are correct.
To solve this problem, we need to consider the motion of the person on the plank and their relative motion with respect to the ground.
Relative Motion on the Plank:
The person is moving along the line A'B' of the plank with a velocity of 2 m/s. The distance between points A and B is 10 m. Therefore, the time taken by the person to cross the plank is given by:
Time = Distance / Velocity
Time = 10 m / 2 m/s
Time = 5 s
So, statement A is correct.
Distance between Points B and C:
The person reaches point C on the ground after crossing the plank. The distance between points B and C can be determined using the Pythagorean theorem:
BC^2 = AB^2 + AC^2
BC^2 = (10 m)^2 + (10 m)^2
BC^2 = 100 m^2 + 100 m^2
BC^2 = 200 m^2
BC = √(200 m^2)
BC = 10√2 m
So, statement B is correct.
Absolute Velocity of the Person:
The absolute velocity of the person is the velocity with respect to the ground. Since the person is moving at a constant velocity of 2 m/s on the plank, and the plank itself is moving at a velocity of 2 m/s with respect to the ground, the absolute velocity of the person is the vector sum of these velocities. Using the principle of vector addition, we can determine the absolute velocity as follows:
Absolute Velocity = √(Velocity on the Plank^2 + Velocity of the Plank^2)
Absolute Velocity = √((2 m/s)^2 + (2 m/s)^2)
Absolute Velocity = √(4 m^2/s^2 + 4 m^2/s^2)
Absolute Velocity = √(8 m^2/s^2)
Absolute Velocity = 2√2 m/s
So, statement C is correct.
Therefore, all the statements A, B, and C are correct.
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A person works along the line A'B' of the large 10 M wide plan moving at 2 m per second in a direction parallel to the length of the reaching the opposite its he germs on to the ground to arrive at point see that lies on the man move set 2 m per second on the plank with respect to it A. The time taken by man to cross the plank is 5 seconds B. The distance between the points B and C is 10 m C. The absolute velocity of man is 2√2 m per second D. All the above are correct?
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A person works along the line A'B' of the large 10 M wide plan moving at 2 m per second in a direction parallel to the length of the reaching the opposite its he germs on to the ground to arrive at point see that lies on the man move set 2 m per second on the plank with respect to it A. The time taken by man to cross the plank is 5 seconds B. The distance between the points B and C is 10 m C. The absolute velocity of man is 2√2 m per second D. All the above are correct? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A person works along the line A'B' of the large 10 M wide plan moving at 2 m per second in a direction parallel to the length of the reaching the opposite its he germs on to the ground to arrive at point see that lies on the man move set 2 m per second on the plank with respect to it A. The time taken by man to cross the plank is 5 seconds B. The distance between the points B and C is 10 m C. The absolute velocity of man is 2√2 m per second D. All the above are correct? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A person works along the line A'B' of the large 10 M wide plan moving at 2 m per second in a direction parallel to the length of the reaching the opposite its he germs on to the ground to arrive at point see that lies on the man move set 2 m per second on the plank with respect to it A. The time taken by man to cross the plank is 5 seconds B. The distance between the points B and C is 10 m C. The absolute velocity of man is 2√2 m per second D. All the above are correct?.
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