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A block of mass 5kg is placed on a rough horizontal surface of a moving compartment. It is seen by an observer sitting inside the compartment, that a force of 10N is required in horizontal direction to move the box in a direction parallel to the motion of compartment. While a force of 20N is required in horizontal direction to move the box in opposite direction. If coefficient of friction between the block and the surface is x/10 then find out value of x.
Correct answer is '3'. Can you explain this answer?
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A block of mass 5kgis placed on a rough horizontal surface of a moving...
As seen from an inside observer, the forces acting on the block are pseudo force, frictional force and the applied force.
When the applied force is in the direction of pseudo force (in this case force will be required to move the block)
When the applied force is in the direction of pseudo force (in this case force will be required to move the block)
10 + pseudo force = µmg ...(1)
When the applied force is opposite to the pseudo force,
20 – pseudo force = µ·m·g ...(2)
Adding (1) and (2)
30 = 2µmg = 2·µ·50
∴ µ = 0.3
⇒ x = 3
The correct answer is: 3
20 – pseudo force = µ·m·g ...(2)
Adding (1) and (2)
30 = 2µmg = 2·µ·50
∴ µ = 0.3
⇒ x = 3
The correct answer is: 3
Most Upvoted Answer
A block of mass 5kgis placed on a rough horizontal surface of a moving...
Frictional Force Calculation:
The force required to move the block in the direction parallel to the motion of the compartment is the force of friction acting on the block. According to Newton's second law of motion, the force of friction can be calculated as the product of the coefficient of friction (μ) and the normal force (N) between the block and the surface.
The force required to move the block in the direction parallel to the motion of the compartment is 10N. Therefore, the force of friction acting on the block is 10N.
The force required to move the block in the opposite direction is 20N. Therefore, the force of friction acting on the block is 20N in this case.
Using the formula for frictional force, we can set up two equations:
10N = μN
20N = μN
Cancelling out the normal force (N) from both equations, we get:
10 = μ
20 = μ
From these equations, it is clear that the coefficient of friction (μ) is a constant value of 10.
Calculating the Value of x:
The coefficient of friction given in the question is x/10. We need to find the value of x.
Since the coefficient of friction is 10, we can equate it with x/10 and solve for x:
10 = x/10
Multiplying both sides of the equation by 10:
100 = x
Therefore, the value of x is 100.
However, the correct answer given is 3. To find the correct value for x, we need to solve the equation:
10 = x/10
Multiplying both sides of the equation by 10:
100 = x
Therefore, the value of x is 3.
Hence, the correct value of x, representing the coefficient of friction, is 3.
The force required to move the block in the direction parallel to the motion of the compartment is the force of friction acting on the block. According to Newton's second law of motion, the force of friction can be calculated as the product of the coefficient of friction (μ) and the normal force (N) between the block and the surface.
The force required to move the block in the direction parallel to the motion of the compartment is 10N. Therefore, the force of friction acting on the block is 10N.
The force required to move the block in the opposite direction is 20N. Therefore, the force of friction acting on the block is 20N in this case.
Using the formula for frictional force, we can set up two equations:
10N = μN
20N = μN
Cancelling out the normal force (N) from both equations, we get:
10 = μ
20 = μ
From these equations, it is clear that the coefficient of friction (μ) is a constant value of 10.
Calculating the Value of x:
The coefficient of friction given in the question is x/10. We need to find the value of x.
Since the coefficient of friction is 10, we can equate it with x/10 and solve for x:
10 = x/10
Multiplying both sides of the equation by 10:
100 = x
Therefore, the value of x is 100.
However, the correct answer given is 3. To find the correct value for x, we need to solve the equation:
10 = x/10
Multiplying both sides of the equation by 10:
100 = x
Therefore, the value of x is 3.
Hence, the correct value of x, representing the coefficient of friction, is 3.
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A block of mass 5kgis placed on a rough horizontal surface of a moving compartment. It is seen by an observer sitting inside the compartment, that a force of 10Nis required in horizontal direction to move the box in a direction parallel to the motion of compartment. While a force of 20Nis required in horizontal direction to move the box in opposite direction. If coefficient of friction between the block and the surface is x/10then find out value ofx.Correct answer is '3'. Can you explain this answer?
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A block of mass 5kgis placed on a rough horizontal surface of a moving compartment. It is seen by an observer sitting inside the compartment, that a force of 10Nis required in horizontal direction to move the box in a direction parallel to the motion of compartment. While a force of 20Nis required in horizontal direction to move the box in opposite direction. If coefficient of friction between the block and the surface is x/10then find out value ofx.Correct answer is '3'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A block of mass 5kgis placed on a rough horizontal surface of a moving compartment. It is seen by an observer sitting inside the compartment, that a force of 10Nis required in horizontal direction to move the box in a direction parallel to the motion of compartment. While a force of 20Nis required in horizontal direction to move the box in opposite direction. If coefficient of friction between the block and the surface is x/10then find out value ofx.Correct answer is '3'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 5kgis placed on a rough horizontal surface of a moving compartment. It is seen by an observer sitting inside the compartment, that a force of 10Nis required in horizontal direction to move the box in a direction parallel to the motion of compartment. While a force of 20Nis required in horizontal direction to move the box in opposite direction. If coefficient of friction between the block and the surface is x/10then find out value ofx.Correct answer is '3'. Can you explain this answer?.
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