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A differential amplifier has inputs v1 = 1050 µV and v2 = 950 µV, with CMRR = 100, what is the error in differential output:
  • a)
    10%
  • b)
    1%
  • c)
    0.1%
  • d)
    0.01%
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A differential amplifier has inputs v1 = 1050 µV and v2 = 950 &m...
MV and v2 = 1100 mV. The differential gain is Ad = 5000 and the common mode gain is Ac = 0. The output voltage of the differential amplifier is Vout = Ad*(v1 - v2) + Ac*(v1 + v2). Let's calculate the output voltage using the given values.

v1 = 1050 mV
v2 = 1100 mV
Ad = 5000
Ac = 0

Vout = Ad*(v1 - v2) + Ac*(v1 + v2)
= 5000*(1050 mV - 1100 mV) + 0*(1050 mV + 1100 mV)
= 5000*(-50 mV) + 0*(2150 mV)
= -250000 mV + 0
= -250000 mV

Therefore, the output voltage of the differential amplifier is -250000 mV.
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A differential amplifier has inputs v1 = 1050 µV and v2 = 950 µV, with CMRR = 100, what is the error in differential output:a)10%b)1%c)0.1%d)0.01%Correct answer is option 'A'. Can you explain this answer?
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