Can you explain the answer of this question below:Equal charges are gi...
V(potential) is inversely proportional to r ( radius).so smaller sphere will have more potential as its radius will be small.
Can you explain the answer of this question below:Equal charges are gi...
Explanation:
When equal charges are given to two spheres of different radii, the potential will be more on the smaller sphere. This can be explained using the formula for electric potential, which is given by:
V = k * Q / r
where V is the electric potential, k is the electrostatic constant, Q is the charge on the sphere, and r is the radius of the sphere.
Explanation:
1. Electric Potential is inversely proportional to radius:
From the formula for electric potential, it can be observed that the potential is inversely proportional to the radius of the sphere. This means that if the radius of the sphere decreases, the potential increases. Conversely, if the radius increases, the potential decreases.
2. Same charge on both spheres:
In the given scenario, equal charges are given to both spheres. This means that the charge (Q) is the same for both spheres.
3. Comparison between smaller and bigger sphere:
Let's consider two spheres - one with a smaller radius (r1) and the other with a larger radius (r2), where r1 < />
3.1. Potential of the smaller sphere:
Using the formula for electric potential, the potential of the smaller sphere can be expressed as:
V1 = k * Q / r1
3.2. Potential of the larger sphere:
Similarly, the potential of the larger sphere can be expressed as:
V2 = k * Q / r2
4. Comparing the potentials:
Comparing the two expressions for potential (V1 and V2), it can be observed that V1 > V2 since r1 < r2.="" this="" means="" that="" the="" potential="" is="" higher="" on="" the="" smaller="" sphere="" compared="" to="" the="" larger="" />
Conclusion:
Therefore, when equal charges are given to two spheres of different radii, the potential will be more on the smaller sphere.